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Moments Moments Principles of EngineeringTM
Unit 4 – Lesson Statics Moments
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Moments Moment Principles of EngineeringTM Unit 4 – Lesson Statics The moment of a force is a measure of the tendency of the force to rotate the body upon which it acts. FORCE The force applied to drive the bolt produces a measurable moment, and the wrench rotates about the axis of the bolt.
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Terminology = F FORCE pivot = D distance lever arm
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Terminology FORCE = F distance lever arm pivot = D The distance must be perpendicular to the force.
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Moment M M = F x D Moments Formula = F FORCE pivot = D distance
Principles of EngineeringTM Unit 4 – Lesson Statics Moments Formula FORCE = F distance pivot = D Moment M = F x D M
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Units for Moments Force Distance Moment English Customary
Principles of EngineeringTM Unit 4 – Lesson Statics Force Distance Moment English Customary Pound force (lbf) Foot (ft) lb-ft SI Newton (N) Meter (m) N-m
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Rotation Direction CCW is positive CW is negative
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Rotation Direction In order to add moments, it is important to know if the direction is clockwise (CW) or counterclockwise (CCW). CCW is positive CW is negative
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+ Right-Hand Rule counterclockwise
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Right-Hand Rule Curl your fingers to match the direction of rotation. + Thumb is pointing Up = Positive Down = Negative Toward You = Positive Away from You = Negative counterclockwise
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THUMB POINTS TOWARD YOU
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Right-Hand Rule FORCE THUMB POINTS TOWARD YOU POSITIVE
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THUMB POINTS AWAY FROM YOU
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Right-Hand Rule THUMB POINTS AWAY FROM YOU FORCE NEGATIVE
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¯ Moment Calculations FORCE Wrench F = 20. lb D = 9.0 in. M = -(F x D)
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Moment Calculations Wrench F = 20. lb FORCE M = -(F x D) Use the right-hand rule to determine positive and negative. D = 9.0 in. = .75 ft M = -(20. lb x .75 ft) M = -15 lb-ft (15 lb-ft clockwise) D = 9.0 in.
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¯ Moment Calculations FORCE Longer Wrench F = 20. lb D = 1.0 ft
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Moment Calculations Longer Wrench F = 20. lb FORCE M = -(F x D) M = -(20. lb x 1.0 ft) M = lb-ft D = 1.0 ft
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¯ Moment Calculations FORCE L - Shaped Wrench F = 20. lb
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Moment Calculations L - Shaped Wrench FORCE F = 20. lb D = 3 in. = .25 ft M = -(F x D) M = -(20. lb x .25 ft) M = -5 lb-ft 3 in.
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¯ Moment Calculations FORCE Z - Shaped Wrench F = 20. lb
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Moment Calculations FORCE Z - Shaped Wrench F = 20. lb D = 8 in in. = 1.5 ft M = -(F x D) M = -(20. lb x 1.5 ft) M = lb-ft 9 in. 8 in. 10. in.
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Moment Calculations + Wheel and Axle D = r = 50. cm = 0.50 m M = F x D
Moments Moment Calculations Principles of EngineeringTM Unit 4 – Lesson Statics Wheel and Axle r = 50. cm D = r = 50. cm = 0.50 m M = F x D Use the right-hand rule to determine positive and negative. M = 100 N x 0.50 m M = 50 N-m + F = 100 N
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Moment Calculations Wheel and Axle Fy = Fsin50.° = (100. N)(.7660)
Moments Moment Calculations Principles of EngineeringTM Unit 4 – Lesson Statics Wheel and Axle r = 50. cm Fy = Fsin50.° = (100. N)(.7660) Fy = N D = r = 50. cm = 0.50 m M = Fy x D M = N x 0.50 m M = 38 N-m 50.o Fy 50.o F = 100. N
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What is Equilibrium? ΣM = 0 M1 + M2 + M3 . . . = 0
Moments What is Equilibrium? Principles of EngineeringTM Unit 4 – Lesson Statics The state of a body or physical system at rest or in unaccelerated motion in which the resultant of all forces acting on the body is zero. The sum of all moments about any point or axis is zero. ΣM = 0 M1 + M2 + M = 0
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Moment Calculations See-Saw Moments Principles of EngineeringTM
Unit 4 – Lesson Statics Moment Calculations See-Saw
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¯ Moment Calculations + See-Saw ΣM = 0 M1 + (–M2) = 0 M1 = M2
Moments Moment Calculations Principles of EngineeringTM Unit 4 – Lesson Statics ΣM = 0 M1 + (–M2) = 0 Use the right-hand rule to determine positive and negative. M1 = M2 F1 x D1 = F2 x D2 25 lb x 4.0 ft = 40. lb x D2 100 lb-ft = 40. lb x D2 See-Saw F2 = 40. lb F1 = 25 lb 40. lb lb + 2.5 ft = D2 D1 = 4.0 ft D2 = ? ft
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Moment Calculations Loaded Beam C 10.00 ft 10.00 ft A B
Moments Moment Calculations Principles of EngineeringTM Unit 4 – Lesson Statics Loaded Beam Select A as the pivot location. Solve for RB. ΣM = 0 MB + (–MC) = 0 MB = MC RB x DAB = FC x DAC RB x ft = 35.0 lb x 3.00 ft RB x ft = 105 lb-ft DAB = ft DAC= 3.00 ft C 10.00 ft ft A B RB = 10.5 lb RA + RB = 35.0 lb RA = 35.0 lb – 10.5 lb = 24.5 lb FC = 35.0 lb RA RB
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Moment Calculations Truss FB = 500. lb B RAX A C D RAY Fc = 600. lb
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Moment Calculations Truss FB = 500. lb B Replace the pinned and roller supports with reaction forces. 12 ft RAX A 24 ft C 8 ft D DAC = 24 ft DCD = 8 ft DCB = 12 ft DAD = 32 ft RAY Fc = 600. lb RDY
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Moment Calculations Truss FB = 500. lb B RAX A C D RAY Fc = 600. lb
Moments Principles of EngineeringTM Unit 4 – Lesson Statics Moment Calculations Truss Select A as the axis of rotation. Solve for RDY. ΣM = 0 MD – MB – MC = 0 MD = MB + MC RDY x DAD = (FB x DCB) + (FC x DAC) RDY x 32 ft = (500. lb x 12 ft) (600. lb x 24 ft) RDY x 32 ft = 6000 lb-ft lb-ft RDY x 32 ft = lb-ft FB = 500. lb B 12 ft 12 ft RAX A 24 ft C 8 ft D 32 ft ft DAC = 24 ft DCD = 8 ft DCB = 12 ft DAD = 32 ft RDY = 640 lb RAY Fc = 600. lb RDY
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