1. Species Diversity

2. Richness and evenness are components of biodiversity.
is variety of organisms present in an ecosystem
Richness
The number of different species present.
Evenness
If a habitat has similar abundance for each species present, the habitat is said to have eveness.
More species therefore highest richness
Greatest eveness as the two populations have similar abundance.

3. Analysis of the biodiversity of two local communities using Simpson's reciprocal index of diversity.
Simpson’s reciprocal index can be used to calculate biodiversity.
D =
N (N - 1)
Σ n (n - 1)
Simpson’s Reciprocal Index
total of organisms of all species
number of organisms of a single species
the sum of (all species)
It takes into account both richness and evenness
The greater the biodiversity the higher the value of D
The lowest possible defined value of D is 1 (only one species found)
The maximum value is equal to the number of species found, this only occurs if all species are equally abundant.

4. Σ n (n - 1) N (N - 1) D = Compare the biodiversity of the two samples:
Analysis of the biodiversity of two local communities using Simpson's reciprocal index of diversity.
Compare the biodiversity of the two samples:
D =
N (N - 1)
Σ n (n - 1)
Simpson’s Reciprocal Index
total of organisms of all species
number of organisms of a single species
the sum of (all species)

5. Compare the biodiversity of the two samples:
Analysis of the biodiversity of two local communities using Simpson's reciprocal index of diversity.
Compare the biodiversity of the two samples:
Species*
Count A 6 B 1 C
Total 8
Species*
Count A 4 B
Total 8
*correct names not required

6. Analysis of the biodiversity of two local communities using Simpson's reciprocal index of diversity.
Compare the biodiversity of the two samples:
D =
N (N - 1)
Σ n (n - 1)
Simpson’s Reciprocal Index
total of organisms of all species
number of organisms of a single species
the sum of (all species)
Sample A
Species*
Count A 6 B 1 C
Total 8
8 (8 - 1) 56
D = =
6 (6 - 1) + 1 (1 - 1) + 1 (1 - 1)
D = 1.87

7. Σ n (n - 1) D = N (N - 1) 8 (8 - 1) 56 D = = 4 (4 - 1) + 4 (4 – 1)
Analysis of the biodiversity of two local communities using Simpson's reciprocal index of diversity.
Compare the biodiversity of the two samples:
D =
N (N - 1)
Σ n (n - 1)
Simpson’s Reciprocal Index
total of organisms of all species
number of organisms of a single species
the sum of (all species)
Sample B
Species*
Count A 4 B
Total 8
8 (8 - 1) 56
D = =
4 (4 - 1) + 4 (4 – 1)
D = 2.33
Sample B has slighter higher biodiversity