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Uniform Distribution Part 2 Intermediate and Advanced Topics Continuous Probability Distributions Uniform Probability Distribution- Introduction Uniform.

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Presentation on theme: "Uniform Distribution Part 2 Intermediate and Advanced Topics Continuous Probability Distributions Uniform Probability Distribution- Introduction Uniform."— Presentation transcript:

1 Uniform Distribution Part 2 Intermediate and Advanced Topics Continuous Probability Distributions Uniform Probability Distribution- Introduction Uniform Probability Distribution- Example

2 The News Vendor Problem
Swell Productions is sponsoring an outdoor conclave for owners of collectible and classic Fords. The concession stand in the T-Bird area will sell clothing such as official Thunderbird racing jerseys. Suppose the probability of jerseys sales quantities is uniformly (and continuously) distributed between 100 and Suppose sales price is $80 per jersey, purchase cost is $40, and unsold jerseys are returned to the manufacturer for $20 per unit. How many Jerseys Swell Production orders? 100 400 Cu: Underage Cost Cu = = 40 Co: Overage Cost Q If Co was also 40 40 40 Gray /(White + Gray) Cu/(Cu+Cp) = 40/(40+40) = 0.5 20 40 Co = = 20  40/(20+60) =2/3

3 The News Vendor Problem
SL* = Cu/(Cu+Co) SL* = 40/(40+20) = 2/3 (Q-100)/( ) = 2/3 Q= 300 100 400 Q

4 The News Vendor Problem
The expected number of participants in a conference is uniformly distributed between 100 and The participants spend one night in the hotel and the cost is paid by the conference. The hotel has offered a rate of $200 per room if a block of rooms is reserved (non-refundable) in advance. The rate in the conference day is $300. All rooms will be single occupied. How many rooms should we reserve in the non-refundable block to minimize our expected total cost. Service level (Probability of demand not exceeding what we have ordered) SL* = Cu/(Cu+Co) Co: Overage cost Co = 200. Cu: Underage cost Cu = = 100 100 700

5 The News Vendor Problem
SL* = Cu/(Cu+Co) SL* = 100/( ) = 1/3 SL* = (Q-a)/(b-a) = (Q-100)/600 = 1/3 ? 1/600 0.3333 a=100 b=700 Q= 300 B-a=600

6 A Non-Trivial Problem – Curve, Solver, Data table
Profit = (12-x) E(Profit) = 0.2(x-4)(12-x) E(profit) = -0.2x2+3.2x-9.6 x = price offered. Probability of wining = 0.2(x-4)

7 Estimating the Demand Curve

8 Estimating the Demand Curve

9 From Economics to Statistics
160 a= 0, b= 160 f(x) =1/160 µ= (0+160)/2 σ2 = (160-0)2/12 If price is set to P, probability of sale is 1/160(160-P) = 1-P/160 160 P What Price maximizes our revenue? If V= 75, What Price maximizes our profit?

10 From Uniform Distribution to Binomial Distribut.
If price is set to P, probability of sale is 1-P/160 Probability of not sale is 1-(1-P/160)= P/160 If 200 people visit this site, what is average sales? What is standard deviation of sales?


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