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Complex numbers Loci.

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Presentation on theme: "Complex numbers Loci."โ€” Presentation transcript:

1 Complex numbers Loci

2 Complex numbers: Loci in the Argand diagram
KUS objectives BAT Use complex numbers to represent a locus of points on an Argand diagram Starter: see previous page

3 Considering a complex number as a vector
WB10 Loci using the argument Considering a complex number as a vector If you are on this line, the angle and therefore argument remains constant Hence the statement describes the half-line from z1 at an angle ฮฑ with the positive real axis

4 WB11 sketch the locus of z when arg ๐‘งโˆ’(2โˆ’๐‘–) = ๐œ‹ 3
describes the half-line from point ๐‘ง 1 2, โˆ’1 at an angle ๐œ‹ 3 with the positive real axis locus of z

5 WB12 the locus of an arc locus of z If and then but and if then
How can z vary but keep ฮธ fixed? Circle theorem: angles in the same segment are equal Hence the locus of z when is an arc passing through z1 and z2 such that the angle subtended by the chord between z1 and z2 on the arc is ฮธ

6 โ†’ arg ๐‘งโˆ’(0+2๐‘–) ๐‘ง+(3+0๐‘–) = ๐œ‹ 4 ๐‘ง 1 =2๐‘–, ๐‘ง 2 =โˆ’3 โ†’ arg ๐‘งโˆ’2๐‘– ๐‘ง+3 = 3๐œ‹ 4
WB a) sketch the locus of z when arg ๐‘งโˆ’2๐‘– ๐‘ง+3 = ๐œ‹ 4 Put in the form arg ๐‘งโˆ’ ๐‘ง 1 ๐‘งโˆ’ ๐‘ง to identify z1 and z2 โ†’ arg ๐‘งโˆ’(0+2๐‘–) ๐‘ง+(3+0๐‘–) = ๐œ‹ 4 locus of z ๐‘ง 1 =2๐‘–, ๐‘ง 2 =โˆ’3 โ†’ b) What would be the equation of the locus of the minor arc? โ†’ arg ๐‘งโˆ’2๐‘– ๐‘ง+3 = 3๐œ‹ 4 Circle theorem: aopposite angles in a cyclic quadrilateral add to ฯ€ (180๏‚ฐ)

7 WB14 generalising / how do we know which side to put the arc?
e.g. sketch the locus of z when arg ๐‘งโˆ’2๐‘– ๐‘ง+3 =ฮธ, ฮธ>0 As in WB13 ๐‘ง 1 =2๐‘–, ๐‘ง 2 =โˆ’3 locus of z Therefore locus is correct So locus is incorrect locus of z ?

8 ๐‘ง 1 =5, ๐‘ง 2 =1 Put in the form arg ๐‘งโˆ’ ๐‘ง 1 ๐‘งโˆ’ ๐‘ง 2 to identify z1 and z2
WB15 a) sketch the locus of z when arg ๐‘งโˆ’5 ๐‘งโˆ’1 = ๐œ‹ 2 Put in the form arg ๐‘งโˆ’ ๐‘ง 1 ๐‘งโˆ’ ๐‘ง to identify z1 and z2 ๐‘ง 1 =5, ๐‘ง 2 =1 โ†’ locus of z b) Find the centre of the resulting locus If ๐œƒ= ๐œ‹ 2 then the chord between z1 and z2 is a diameter The centre of the circle is (3,0)

9 WB16 given that arg ๐‘งโˆ’2๐‘– ๐‘ง+2 = ๐œ‹ 2 a) sketch the locus of P
b) deduce the value of ๐‘ง+1โˆ’๐‘– ๐‘ง 1 =2๐‘–, ๐‘ง 2 =โˆ’2 โ†’ Put in the form arg ๐‘งโˆ’ ๐‘ง 1 ๐‘งโˆ’ ๐‘ง to identify z1 and z2 also ฮธ= ๐œ‹ 2 so the locus is a semicircle And the chord between z1 ๐‘Ž๐‘›๐‘‘ z2 is a diameter so locus is correct b) ๐‘ง+1โˆ’๐‘– is the distance from a point on the locus to the point (-1,1) But (-1,1) is the centre of the circle, So ๐‘ง+1โˆ’๐‘– must equal the radius of the circle ๐‘ง+1โˆ’๐‘– = 2

10 WB17 You may asked to identify a point satisfying two rules
find the complex number z which satisfies both ๐‘งโˆ’3+2๐‘– =4 and ๐‘Ž๐‘Ÿ๐‘” ๐‘งโˆ’1 = ๐œ‹ 4 First ๐‘งโˆ’(3โˆ’2๐‘–) =4 circle centre (3, -2) radius 4 The half-line from (1, 0) passes through the centre of the circle As the angle is , the triangle is isosceles Using Pythagoras, ๐‘งโˆ’ ๐‘ง 1 =๐‘Ž describes the circle with centre z1 and radius a ๐‘Ž๐‘Ÿ๐‘” ๐‘งโˆ’ ๐‘ง 1 =4 describes the half-line from ๐‘ง 1 at an angle ๏ก with the real axis

11 WB18 Max and Min values The point P represents a complex number z in an Argand diagram. Given that ๐‘ง+1โˆ’๐‘– =1 Find a Cartesian equation for the locus of P and sketch it in an Argand diagram b) Find the greatest and least values of ๐‘ง c) Find the greatest and least values of ๐‘งโˆ’1 ๐‘ง+1โˆ’๐‘– = ๐‘งโˆ’(1+๐‘–) a circle centre(1, -1) radius 1 circle has Cartesian eqn (๐‘ฅ+1) 2 + (๐‘ฆโˆ’1) 2 =1 is distance to origin is distance to (1,0)

12 KUS objectives BAT Use complex numbers to represent a locus of points on an Argand diagram self-assess One thing learned is โ€“ One thing to improve is โ€“

13 END


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