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Experiment 2 Method for the Expression of concentration Β 1- Formality

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Presentation on theme: "Experiment 2 Method for the Expression of concentration Β 1- Formality"β€” Presentation transcript:

1 Experiment 2 Method for the Expression of concentration Β 1- Formality the number of gram- formula weights of solute in one liter of solution 𝑓= 𝑀𝑑 𝐹𝑀𝑑 Γ— 1000 π‘‰π‘šπ‘™

2 𝑁= 𝑀𝑑 π‘’π‘ž.𝑀𝑑 Γ— 1000 π‘‰π‘šπ‘™ 𝑀= 𝑀𝑑 𝑀.𝑀𝑑 Γ— 1000 π‘‰π‘šπ‘™
2- Morality the number of gram- molecular weights (or moles) in one liter of solution 𝑀= 𝑀𝑑 𝑀.𝑀𝑑 Γ— 1000 π‘‰π‘šπ‘™ 3-Normality: the number of gram- equivalent weight in one liter of the solution 𝑁= 𝑀𝑑 π‘’π‘ž.𝑀𝑑 Γ— 1000 π‘‰π‘šπ‘™

3 Percent Concentration
Weight percent= π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘’ π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘› Γ—100 Volume percent = π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘’ π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘› Γ—100 Weigh- Volume percent= π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘’.𝑔 π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘› π‘šπ‘™ Γ—100

4 C1V1 = C2V 2 PPm= π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘’ π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘› Γ—1.000.000
Parts per million Β Β  PPm= π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘’ π‘€π‘’π‘–π‘”β„Žπ‘‘ π‘œπ‘“ π‘†π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘› Γ— The Dilution before dilution = after dilution C1V1 = C2V 2

5 1-Solids a- Preparation (0.1N)of NaOH in250 ml
V ml = 250 Eq. wt = Wt = X

6 N(HCL ) = π‘†π‘’π‘π‘–π‘“π‘–π‘π‘”π‘Ÿπ‘Žπ‘£π‘–π‘‘π‘¦π‘‹ % 𝑀 𝑀 𝑋 1000 𝐸𝑄 .π‘Šπ‘‡π‘œπ‘“π»πΆπΏ
2– Liquids b-Preparation of (0.1N) HCL from concentrated HCL N(HCL ) = π‘†π‘’π‘π‘–π‘“π‘–π‘π‘”π‘Ÿπ‘Žπ‘£π‘–π‘‘π‘¦π‘‹ % 𝑀 𝑀 𝑋 𝐸𝑄 .π‘Šπ‘‡π‘œπ‘“π»πΆπΏ Specific gravity = 1.18 Eq.wt of HCL = 36.5 38 % 𝑀 𝑀 of HCL is obtained from the reagent bottle ... N concentrated HCL = 12

7 To calculate the volume of concentrated HCL that should be taken to prepare 250 ml of (0.1N) HCL .
Β Conc.HCL = diluted HCL N1 V = N2 V2 12 X V = X 250 V1 = ?

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