1. Balancing Redox Reactions
Problem 4.74 a
Balancing Redox Reactions

2. More Oxidation Numbers
Problem 4.74 a)
“Electrons lost = Electrons gained”
(2) Nitrate -1 8
HNO K2CrO Fe(NO3)  1 3 +1 +5 -2 +1 +6 -2 +2 +5 -2
Oxidation
Fe2+ loses 1 electron to become Fe3+
 Need 3 Fe2+ to lose 3 electrons
(3) Nitrate -1
(3) Nitrate -1 2
KNO Fe(NO3) Cr(NO3) H2O 3 4 +1 +5 -2 +3 +5 -2 +3 +5 -2 +1 -2
Last Steps......
Balance “K”
Reduction
Balance “NO3”
Cr6+ gains 3 electrons to become Cr3+
Balance “H”