1. Original Puzzle

2. F6 8 (C5,D2,E9)

3. G8 8 (B7,E9,H1)

4. I4 8 (C5,F6,G8)

5. A3 8 (B7,C5,H1)

6. E2 4 (D9,E4)

7. D1 1 (E6,F5,H1)

8. C2 1 (B9,H3)

9. D3 6 (A2)

10. F2 5 (what's left in box)

11. F5 6 (D3,E7)

12. D5 3 (C4,E3)

13. I9 6 (C8,E7,H4)

14. G1 6 (D6,H4,I9)

15. G3 2 (Phan 2's H5/6, I8)

16. I3 5 (C1,F2)

17. I1 4 (E2)

18. B2 2 (F1,G3)
Hard part, Phantom 5,9 in D8,E8 because of 5,9 in row F. Thus, both 5,9 are blocked elsewhere in column 8. The 5 at C1 blocks all of row C, so phantom 5’s must exist at either A7 or A9, blocking row A elsewhere.

19. H6 5 (5's blocked by A?,C1,I3)
Where can 5 go in column 6 ?? Only at H6. A? means the phantom 5 in either A7 or A9.

20. G7 5 (H6,I3)

21. A9 5 (A7 blocked by G7)
Either A7 or A9 must be a 5, so G7 forces 5 at A9.

22. G4 1 (what's left in row G)

23. A5 1 (B9,C2,G4,E6)

24. H5 2 (I8)
2 in I8 blocks bottom row, forcing 2 at H5.

25. C9 2 (D7,I8)

26. I7 1 (B9,F8)

27. I6 3 (D5)
3 in D5 forces 3 at I6.

28. I5 9 (what's left in box)

29. I2 7 (what's left in row I)

30. H2 9 (what's left in box)

31. E5 5 (phan 5/9 pair in D4,E5)
9 in I5 eliminates the possibility of E5 being a 9, so it must be 5.

32. D4 9 (what's left in box)

33. D8 5 (what's left in row D)

34. E8 9 (what's left in row E)

35. B4 5 (A9,C1,E5,H6)

36. A4 7 (what's left in col 4)

37. B5 4 (what's left in col 5)

38. A6 2 (B2,C9)

39. C6 9 (what's left in box)

40. B3 7 (phan 4/7 pair in B3,C3)
4 in B5 blocks 4 in B3, so B3 must be 7.

41. C3 4 (what's left in col 3)

42. A7 9 (C6,E8,G9)

43. B1 9 (A7)

44. A1 3 (what's left in box)

45. A8 4 (what's left in row A)

46. B8 3 (what's left in row B)

47. C7 7 (what's left in box)

48. F7 3 (phan 3/7 in row F)
C7 is 7, so F7 can NOT be 7 of the 3/7 pair. So, F7 must be 3.

49. F9 7 (what's left in box)

50. (row H completed by columns)
A8,D9 give H7=4; C7,F9 give H8=7; B8,F7 give H9=3. Puzzles Solved.