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Chapter 8 Chemical Bonding
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Overview Lewis Symbols & Octet Ionic Bonding Covalent Bonding
Electron Configurations and Ions Ion Sizes Covalent Bonding Multiple Bonds Bond Polarity Electronegativity
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Exceptions to Lewis Rules
Lewis Structures Formal Charge Resonance Structures Exceptions to Lewis Rules Electron Deficient Expanded Valence Radicals Covalent Bond Strengths Bond Enthalpies Bond Length Oxidation Numbers
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Lewis Symbols and Octet Rule
symbols showing valence electrons for an atom or ion for active metals & representative elements number of valence electron = group number for representative elements stability requires 8 electrons -- an octet like the nobel gases
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Lewis Dot Symbols: C Na N F O 1s22s2p63s1 1s22s22p2 1s22s22p3
C Na N 1s22s2p63s1 1s22s22p2 1s22s22p3 F O 1s22s22p s22s22p5
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Ionic Bonding Ionic Bond
strong attractive, electrostatic force between cations and anions Ions form to achieve noble gas configuration – an octet ion symbols shown as Lewis symbols generally forms between metals and non-metals overall, the formation of ionic bonds releases energy, exothermic
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® Cl Cl Na Na Atoms Ions Na(s) + ½Cl2(g) ® NaCl(s) DHfo = - 411 kJ/mol
Cl + Cl - Na Na + both have octets electropositive metal nonmetal with high electron affinity Na(s) + ½Cl2(g) ® NaCl(s) DHfo = kJ/mol
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® Cl Cl Mg Mg Cl Atoms Ions _ 2+ _ electropositive metal
Mg Cl 2+ Mg _ Cl electropositive metal all have octets nonmetals with high electron affinity
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Energetics of Ionic Bond Formation
formation of ionic compounds is exothermic electrostatic attraction E = k Q1Q2 lattice energy d Q1 charge of cation, Q2 charge of anion, d distance between cation and anion steps for formation change Na from solid to gas -- endothermic dissociate Cl2(g) -- endothermic remove electron from Na -- endothermic add electron to Cl -- exothermic combine ions, electrostatic attraction -- very exothermic sum of all above is exothermic
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Practice Ex. 8.1: Which would you expect to have the greatest lattice energy: AgCl CuO CrN AgCl Q1 = +1 Q2 = -1 CuO Q1 = +2 Q2 = -2 CrN Q1 = +3 Q2 = -3 CrN because E = k Q1Q2 is largest d
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Problem: If NaCl has a high lattice E and is very stable, would you expect NaCl2 to be even more stable? NaCl2 does not form -- even though the lattice energy would be higher, the formation of Na2+ would be so costly, so endothermic, that it would overwhelm the exothermic lattice energy
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Formation of Ions Representative Elements Transition Metals
last electron entered in an electron configuration is the first electron lost in ion formation 11Na 1s2 2s2 2p6 3s Na+ 1s2 2s2 2p6 3s0 Transition Metals the s electrons are always lost first, before any d electrons are lost 26Fe [Ar] 4s2 3d Fe2+ [Ar] 4s0 3d Fe3+ [Ar] 4s0 3d5
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Sizes of Ions Cations Þ smaller than atoms from which they are derived
removal of one or more electrons will increase Zeff ‘felt’ by remaining electrons causes contraction of cation Anions Þ larger than atoms from which they are derived addition of one or more electrons will decrease Zeff ‘felt’ by outer electrons causes some repulsion between electrons creating some expansion of size
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Covalent Bonding A pair of electrons shared between two atoms
Generally occurs between two non-metals so that atoms can attain an octet Releases energy upon formation -- exothermic Two atoms can share: one pair of electrons , single bond two pair of electrons, double bond three pair of electrons, triple bond
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H H H One Shared Pair of Electrons = Single Bond
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O O O Two Shared Pair of Electrons = Double Bond
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N N N N Three Shared Pair of Electrons = Triple Bond · · · · · · · · ·
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The more electrons, the shorter & stronger the bond
Bond strength single < double < triple Bond length single > double > triple N - N N = N NN Å Å Å 163 kJ kJ kJ
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H O H Cl Two types of covalent bonds non-polar · polar ·
electrons are shared equally atoms sharing electrons have equal attraction for them H O polar electrons are not shared equally atoms sharing electrons have different attractions for them H Cl Cl has a greater attraction for the electrons
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Bond Polarity & Electronegativity
ability of an atom in a bond to attract the shared electrons related to electron affinity & ionization energy but not the same as decreases down a group (except for transition elements) increases across a row EN of atom are relative to one another range from 0.7 to 4.0
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Bond Polarity electrons shared between two atoms with different EN are shared unequally unequal sharing creats a separation of charge -- polar bond greater the DEN of the atoms, the greater the polarity of the bond EN EN 3.0 H Cl d+ d - H Cl partial (+) charge partial (-) charge shared electrons spend more time around Cl
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Drawing Lewis Structures
Rules: write Lewis symbols for each atom in formula count total no. of electrons count total no. of unpaired electrons divide by 2 = no. of covalent bonds arrange atoms (more electropositive in the center) place correct no. of covalent bonds place remaining electrons around atoms so that all atoms have octets
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N H NH3 N H 8 total electrons 6 upe- ¸ 2 = 3 cov. bonds
NH3 8 total electrons 6 upe- ¸ = 3 cov. bonds N H hydrogens are always terminal
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C O CO2 = C = O 16 total electrons 8 upe- ¸ 2 = 4 cov. bonds
CO2 16 total electrons 8 upe- ¸ = 4 cov. bonds = C = O more electropositive atom
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C O CO32- 24 total electrons 8 upe- ¸ = 4 cov. bonds C O
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Formal Charge Bookkeeping method to keep track of electrons in Lewis structures Rules all unshared electrons assigned to the atom on which they reside half of all shared electrons are assigned to each atom in bond no. valence e- on free atom - no. valence e- on bound atom Formal Charge
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NH3 N H H H N 5 e e H N H H H 1 e e
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CO2 C O O = C = O C 4 e e O 6 e e
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CO32- C O O O O C O O O 6 e- 6 e- 0 C 4 e- 4 e- 0 O 6 e- 7 e- -1 · · ·
O 6 e e C 4 e e -2 O C O O -1 O 6 e e
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O = C = - C º Formal charge must equal any charge on the structure
prediction of stability most stable structures have lowest sum of absolute values of formal charges O = C = - C º -1 +1 = 0 = 2 preferred structure
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