Download presentation
Presentation is loading. Please wait.
Published byΚλεισθένης Διαμαντόπουλος Modified over 5 years ago
1
Evac Evac 1 1 qc1 = 4.07 eV qfs1 = 4.782 eV qc2 = 3.63 eV qfs2
1 1 qc1 = 4.07 eV qfs1 = eV qc2 = 3.63 eV qfs2 = eV 2 2 3 3 EC2 4 4 EC1 Eg2 = eV EF2 EF1 Eg1 = eV 5 5 EV2 EV1 6 6 VM Ayres, ECE , F13
2
Now that plots are accurately scaled, remove values for clarity.
Evac Evac EC2 EC1 EF2 EF1 EV2 EV1 Now that plots are accurately scaled, remove values for clarity. VM Ayres, ECE , F13
3
Align Fermi energy levels: EF1 = EF2:
VM Ayres, ECE , F13
4
Put in Junction J in middle since both undoped (intrinsic):
VM Ayres, ECE , F13
5
Join Evac smoothly: Junction J VM Ayres, ECE , F13
6
Anderson Model: Use qc1 “measuring stick” to put in EC1:
Junction J VM Ayres, ECE , F13
7
Anderson Model: Use qc2 “measuring stick” to put in EC2:
Junction J VM Ayres, ECE , F13
8
Put in straight piece connector:
Junction J DEC = 0.44 eV Anderson model: DEC = qc1 – qc2 = 0.44 eV VM Ayres, ECE , F13
9
A shallow quantum well for e- has developed in the conduction band EC1:
Junction J DEC = 0.44 eV VM Ayres, ECE , F13
10
Use the energy bandgap Eg1 “measuring stick” to relate EC1 and EV1:
Junction J DEC = 0.44 eV VM Ayres, ECE , F13
11
Use the energy bandgap Eg2 “measuring stick” to relate EC2 and EV2:
Junction J VM Ayres, ECE , F13
12
Put straight piece connector in:
Junction J DEC = eV Anderson model: DEgap = DEC + DEV => DEV = DEgap – DEC DEV = [(1.923 – 1.424) – 0.44] eV = eV VM Ayres, ECE , F13
13
A very shallow quantum well for holes has developed in EV2:
Junction J DEC = eV VM Ayres, ECE , F13
14
(a) Band-bending diagram:
Junction J DEC = 0.44 eV DEV = eV (b) Anderson model: DEC = 0.44 eV DEV = eV VM Ayres, ECE , F13
15
Result is similar to n-n and p-p isotype heterojunctions:
Sze, Physics of Semiconductor Devices VM Ayres, ECE , F13
16
These are the traditional n-p and p-n heterojunctions:
Sze, Physics of Semiconductor Devices VM Ayres, ECE , F13
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.