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Published byBartolommeo Pieri Modified over 5 years ago
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Part (a) This estimate of 30.8’ is HIGHER than the actual value because r(t) is CONCAVE DOWN. (r - ) = (t - ) 30 5 2 r = 2t + 20 r 2(5.4) + 20 r 30.8 feet
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Part (b) Find dV/dt when t=5: Volume = 4/3 p r3 dV/dt = 4 p r2 (dr/dt) dV/dt = 4 p (30)2 (2) dV/dt = 7200 p ft3/min
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(2)(4) + (3)(2) + (2)(1.2) + (4)(.6) + (1)(.5) 8 + 6 + 2.4 + 2.4 + .5
Part (c) 2 5 7 11 12 (0,5.7) (2,4) (5,2) (7,1.2) (11,0.6) (12,0.5) Right Riemann sum: r’(t) dt 12 (2)(4) + (3)(2) + (2)(1.2) + (4)(.6) + (1)(.5) This represents the total change in the balloon’s radius during the 12 minute interval. 19.3
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(IGNORED) Part (d) r’(t) dt.
2 5 7 11 12 (0,5.7) (2,4) (5,2) (7,1.2) (11,0.6) (12,0.5) (IGNORED) r’(t) dt. 12 Our approximation of 19.3 feet was less than Since the curve was decreasing, we purposely ignored these white areas that should have been considered.
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