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Published byRaimo Hukkanen Modified over 5 years ago
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8.3 The Addition Method Also referred to as Elimination Method
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The Addition Method Write the second equation below the first.
Add the equations together and solve for the remaining variable.
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Solve: + x + y = 5 x - y = 1 x - y = 1 x - y = 1 x - y = 1 x - y = 1
= 6 x = 3 3 + y = 5 y = 2 (3,2)
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x + y = 5 x + y = 5 2x - y = 4 3x = 9 x = 3 3 + y = 5 y = 2 (3,2)
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2 Special Cases No solution Case 1: NO SOLUTION
Both variables cancel out but the constant does not Leaving a false equation. 4x - 2y = 2 -4x + 2y = -16 0 + 0 = -14 No solution
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Case 2: INFINITELY MANY SOLUTIONS
Both variables and the constant cancel out Leaving a true equation 5x - 7y = 6 -5x + 7y = -6 0 + 0 = 0 Infinitely many solutions
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They all do not cancel out so easily
If the equations do not eliminate a variable when you add them together: Multiply the whole equation by a number that will help you cancel it out.
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2 4x - 2y = 7 4x - 2y = 7 3x + y = 4 6x + 2y = 8 10x = 15 x = 1.5
(1.5,-0.5)
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-1 2x + 3y = 8 2x + 3y = 8 x + 3y = 7 -x - 3y = -7 x = 1 2(1) + 3y = 8
(1,2)
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3 4 4x + 2y = 18 12x + 6y = 54 -3x + 5y = 6 -12x + 20y = 24 26y = 78
(3,3) y = 3
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3 -5 5x + 3y = 2 15x + 9y = 6 -15x - 35y = 20 3x + 7y = -4 -26y = 26
(1,-1) x = 1
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5(a-b)=10 and a+b=2
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The sum of two numbers is 72. The difference is 58. Find the numbers.
x + y = 72 x - y = 58 7 and 65
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The sum of the length and width of a rectangle is 25 cm
The sum of the length and width of a rectangle is 25 cm. The length is 2 less than twice the width. Find the length and width.
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Assignment: Page 371 (2-40) even
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