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AS Maths Decision Paper June 2013 Model Answers
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Grade Boundaries Grade A B C D E Marks 64 59 54 50 46
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A 1 B 2 C 3 D 4 E 5 F 6
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Initial Match A 1 B 2 C 3 D 4 E 5 F 6 A 1 B 2 C 3 D 4 E 5 F 6 One Solution 𝑭→𝟏↛𝑩→𝟒 𝑨→𝟑↛𝑪→𝟐↛𝑬→𝟔 One Final Match A3, B4, C2, D5, E6, F1
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5 Comp Swaps 2, 12, 17, 18, 5, 13 2, 12, 17, 18, 5, 13 2, 5, 12, 17, 18, 13 2, 5, 12, 13, 17, 18 2, 5, 12, 13, 17, 18
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EG = 2.3 AB = 2.5 IJ = 2.9 AC = 3.1 AD = 3.2 HJ = 3.4 GJ = 3.6 BE = 3.9 FI = 5.4 Total = 30.3 Total = 30.3
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B E H A D G J C F I
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FI
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AD
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A → B → C → D → E → F → A 15 13 10 26 27 12 = 103 It is a TOUR, that maybe IMPROVED upon
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A → C → D → F → B → E → A 11 10 15 15 24 27 = 102
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77 e) Because it has a LOWER BOUND of 77 10 C D 12 10 + 12 + 13 + 19 =
A F 19 = 23 12 13 E 11 C B F 77
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Police Car A A → B → D → K → G Police Car E E → C → D → K → G
21 19 Police Car E E → C → D → K → G 10 12 11 5 15 Police Car J J → L → I → H → G 16 7 15 21 14 6 15 9 10 20 21
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ii) B would appear 4 times ( 𝑛 2 = 8 2 =4)
ODD VERTICES at A, C, L and G AC (12) + LG (15) = 27 AL (11) + CG (15) = 26 Repeat AG (21) + CL (9) = 30 Total = = 160 ii) B would appear 4 times ( 𝑛 2 = 8 2 =4) Total of all times = 134 minutes
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A B C D E Line 10 36 16 2 Line 20 32 Line 30 4 Line 40 Line 60 16 Line 70 4 4 Line 20 16 Line 30 Line 40 Print B 4
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A B C D E Line 10 11 7 1 Line 20 7 Line 30 4 Line 40 Line 60 7 Line 70 4 1 Line 20 4 Line 30 3 Line 40 Line 60 4 Line 70 3 1 Line 20 3 Line 30 1 Line 40
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A B C D E Line 60 3 Line 70 1 3 Line 20 3 Line 30 Line 40 Print B 1 HCF (of A and B )
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6𝑥+4𝑦+3𝑧≥420 6𝑥+4𝑦+3𝑦≥420 6𝑥+7𝑦≥420 6𝑥+6𝑦+4𝑦≥480 6𝑥+6𝑦+4𝑧≥480 6𝑥+10𝑦≥480 6𝑥+4𝑦+4𝑦≤720 6𝑥+4𝑦+4𝑧≤720 3𝑥+5𝑦≥240 6𝑥+8𝑦≤720 3𝑥+4𝑦≤360 𝑆𝑜 𝑦=𝑧
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𝑃=4𝑥+5𝑦 𝑂𝑏𝑗𝑒𝑐𝑡𝑖𝑣𝑒 𝑙𝑖𝑛𝑒 4𝑥+5𝑦=20 Or 4𝑥+5𝑦=100 𝑊ℎ𝑒𝑛 𝑥=0, 𝑦=20
3𝑥+4𝑦=360 𝑂𝑏𝑗𝑒𝑐𝑡𝑖𝑣𝑒 𝑙𝑖𝑛𝑒 4𝑥+5𝑦=20 Or 4𝑥+5𝑦=100 6𝑥+7𝑦=420 𝑊ℎ𝑒𝑛 𝑥=0, 𝑦=20 𝑊ℎ𝑒𝑛 𝑦=0,𝑥=25 𝑭𝒆𝒂𝒔𝒊𝒃𝒍𝒆 𝑹𝒆𝒈𝒊𝒐𝒏 𝑶𝒃𝒋𝒆𝒄𝒕𝒊𝒗𝒆 𝑳𝒊𝒏𝒆 3𝑥+5𝑦=240 𝑦=0
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𝑃=4𝑥+5𝑦 Maximum Profit £480 (120 Gold (𝑥), 0 Silver(𝑦), 0 Bronze 𝑧 . 𝑃=2𝑥+12𝑦 Maximum Profit £1080 (0 Gold (𝑥), 90 Silver(𝑦), 90 Bronze 𝑧 .
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