1. Bellwork #34 April 24th, 2017 Grab a BW sheet from the Algebra I bin.
Quiz on Sections 10.1 – 10.5 on Thursday!
A review will be given tomorrow.

2. Section 10.4 Review Solving Quadratics (when b=0):
Step 1: Isolate the term that is being square on one side of the equation.
Step 2: Square root both sides of the equation.
Step 3: Finish solving for x, if necessary.

5. Find the EXACT solutions to the following equations:
1.)

6. 2.) (x - 6) = 3

7. 3.) 2(x + 1)2 + 3 = 51

8. Standard Form of a Quadratic Function:
y = ax2 + bx + c
Standard Form of a Quadratic Equation:
0 = ax2 + bx + c

10. 10.5 – Factoring to Solve Quadratic Equations
Algebra I

11. Objective 1: Solving Quadratic Equations by Factoring
In the previous lesson, you solved quadratic equations by finding square roots. This only works when b = 0. You can solve quadratic equations by using the Zero Product Property, if b ≠ 0.
Key Concepts: Property – Zero-Product Property:
For every real number a and b, if ab = 0, then a = 0 or b = 0.
Example: If (x+3)(x+2) = 0, then x + 3 = 0 or x + 2 =0

12. Example 1: Using the Zero-Product Property
Solve each equation: 1.) (x + 3)(x – 8) = 0 x =

13. Quick Check #1:
2.) (4x + 7)(x – 6) = 0 3.) (3x – 1)(x + 11) = 0 x = x =

14. Quick Check #2:
4.) 2x(x – 2) = 0 x =

16. Answer: Factoring Quadratics!!
You can also use the Zero-Product Property to solve equations of the form 𝑎 𝑥 2 +𝑏𝑥+𝑐=0 if the quadratic expression 𝑎 𝑥 2 +𝑏𝑥+𝑐 can be factored.

17. Example 2: Solve for x by factoring
5.) 4 𝑥 2 −12𝑥−27

19. Quick Check #3: Solve for x by factoring
6.) 𝑥 2 −8=2𝑥

20. 7.) 7 𝑥 2 −21𝑥=0

21. 8.) 6 𝑥 2 +5𝑥−21=0

22. 9.) 3 𝑥 2 −11=2 𝑥 2 −4𝑥+1

23. 10.) 2 𝑥 3 −5 𝑥 2 =18𝑥−45

24. HW #24: due tomorrow!
Section 10.4 – pg. 531 #s 1-2, 5, Section 10.5 – pgs. 538 – 539 #s 1-3, 9, 10, 13, 14, 17, 27, 32