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K+  p+ + “nothing” in E949 (1) K+  p+nn (above Kp2)

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Presentation on theme: "K+  p+ + “nothing” in E949 (1) K+  p+nn (above Kp2)"— Presentation transcript:

1 K+  p+ + “nothing” in E949 (1) K+  p+nn (above Kp2)
Published in PRL, (2004) Charged track momentum from various K decay modes (2) p0 nn (on Kp2 peak) This report. Need tighter photon rejection. (3) K+  p+nn (below Kp2) Analysis ongoing. Require more sophisticated treatment in p+ multiple scatterings.

2 Bifurcation Analysis Bifurcation Analysis Ex.) Km2(g) rejection
Cut1 : Range deviation Uncorrelated Cut-1 and Cut-2 Rcut-1 = (C+D)/C Signal Region A/B = C/D A = BC/D = B / (Rcut-1 -1) Cut2 : Neural Net output

3 Kp2 triggered events

4 Pion decay sequence

5 Pion Decay Sequence

6 Background Mechanism

7 Background Mechanism

8 Pion Decay Sequence : Neural Network

9 Range Stack dE/dx cut

10 Range Stack dE/dx cut

11 Single-beam background rejection


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