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2 Chapter Chapter 2 Equations, Inequalities and Problem Solving
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The Addition & Multiplication Properties of Equality
Section 2.2 The Addition & Multiplication Properties of Equality
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Defining Linear Equations and Using the Addition Property
Objective 1 Defining Linear Equations and Using the Addition Property
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Linear Equations An equation is of the form “expression = expression.”
An equation contains an equal sign and an expression does not. Equations Expressions Objective A
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Linear Equations Linear Equation in One Variable
A linear equation in one variable can be written in the form ax + b = c where a, b, and c are real numbers and a ≠ 0.
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Using the Addition Property to Solve Equations
Addition Property of Equality Let a, b, and c represent numbers. Then a = b and a + c = b + c are equivalent equations. Objective A
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Example Solve x – 4 = 7 for x. Check: Objective A
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Example Solve: y – 1.2 = –3.2 – 6.6 Objective A
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Example Solve: Objective A
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Example Solve: 6x + 8 – 5x = 8 – 3 x + 8 – 8 = 5 – 8 Objective A
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Example Solve: 3(3x – 5) = 10x Objective A
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Example Solve: 4p – 11 – p = 2 + 2p – 20
3p – 11 = 2p – Simplify both sides. 3p + (– 2p) – 11 = 2p + (– 2p) – 18 Add –2p to both sides. p – 11 = – Simplify both sides. p – = – Add 11 to both sides. p = – Simplify both sides.
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Example Solve: 5(3 + z) – (8z + 9) = – 4z
15 + 5z – 8z – 9 = – 4z Use distributive property. 6 – 3z = – 4z Simplify left side. 6 – 3z + 4z = – 4z + 4z Add 4z to both sides. 6 + z = Simplify both sides. 6 + (–6) + z = 0 + (–6) Add –6 to both sides. z = – Simplify both sides.
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Using the Multiplication Property
Objective Using the Multiplication Property
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Example Solve: Objective A
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Example Solve –4x = 16 for x. Check: Objective A
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Example Solve: –1.2x = –36 Objective A
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Example Solve: Multiply both sides by 7. Simplify both sides.
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Using Both the Addition and Multiplication Properties
Objective 3 Using Both the Addition and Multiplication Properties
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Example Solve: 4x – 8x = 16 Objective A
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Example Solve: 3z – 1 = 26 3z – 1 = 26 3z – 1 + 1 = 26 + 1 3z = 27
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Example Solve: 12x + 30 + 8x – 6 = 10 20x + 24 = 10
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Example Solve: 5(2x + 3) = –1 + 7 5(2x) + 5(3) = –1 + 7 10x + 15 = 6
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Writing Word Phrases as Algebraic Expressions
Objective 4 Writing Word Phrases as Algebraic Expressions
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Example If x is the first two consecutive integers, express the
sum of the two integers in terms of x. Simplify if possible. The second consecutive integer is always 1 more than the first. If x is the first of two consecutive integers, the two consecutive integers are x and x + 1. x + (x + 1) = 2x + 1
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Example (cont) If x is the first two consecutive odd integers,
express the sum of the two integers in terms of x. Simplify if possible. The second consecutive odd integer is always 2 more than the first. If x is the first of two consecutive odd integers, the two consecutive integers are x and x + 2. x + (x + 2) = 2x + 2
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