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NOTES: - Thermochemical Equations (17.2)

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Presentation on theme: "NOTES: - Thermochemical Equations (17.2)"— Presentation transcript:

1 NOTES: - Thermochemical Equations (17.2)

2 ENTHALPY ENTHALPY = a type of chemical energy, sometimes referred to as “heat content” Many reactions involve the production or absorption of heat. This heat is called the heat of reaction, or enthalpy (H). Example: CH O2  CO H2O kJ Heat Term

3 Heat can be a product… When the heat is a product, it appears on the RIGHT side of the equation, and the reaction is said to be EXOTHERMIC. 2Mg + O2  2MgO + Heat

4 Heat can also be a reactant….
When the heat is a reactant, it appears on the LEFT side of the equation, and the equation is said to be ENDOTHERMIC. NH4NO3 + Heat  NH4+ + NO3-

5 H = -333 kcal (why negative?)
An equation involving heat can be written 2 ways: CH4 + O2  H2O + CO kcal -or- CH4 + O2  H2O + CO2 H = -333 kcal (why negative?)

6 Reaction Diagram: Exothermic
Change of Heat (H) Energy Exothermic Reaction (H = -)

7 Reaction Diagram: Endothermic
Change of Heat (H) Energy Endothermic Reaction (H = +)

8 REVIEW: Exo vs. Endothermic
exothermic reactions: q = ΔH < 0 (negative values) surroundings get hot heat appears on the right side of the equation (as a product)

9 REVIEW: Exo vs. Endothermic
endothermic reactions: q = ΔH > 0 (positive values) surroundings get cold heat appears on the left side of the equation (as a reactant)

10 Thermochemical Equations
● A chemical equation that shows the enthalpy (H) is a thermochemical equation. Example: 2H2(g) + O2(g)  2H2O(g) ∆H = -572 kJ

11 Rules of Thermochemistry
Rule #1 - The magnitude of H is directly proportional to the amount of reactant of product.

12 Rules of Thermochemistry
Example 1: H2 + Cl2  2HCl H = kJ Calculate H when 1.00 g of Cl2 reacts.

13 H Cl2  HCl kJ ΔH = kJ (exothermic)

14 Rules of Thermochemistry
Example 2: When an ice cube weighing 24.6 g of ice melts, it absorbs 8.19 kJ of heat. Calculate H when 1.0 mol of ice melts.

15 H2O(s) kJ  H2O(l)

16 Rules of Thermochemistry
Example 3: Methanol burns to produce carbon dioxide and water: 2CH3OH + 3O2  2CO2 + 4H2O kJ What mass of methanol is needed to produce 1820 kJ?

17 2CH3OH + 3O2  CO2 + H2O kJ

18 Rules of Thermochemistry
Example 4: How much heat is produced when 58.0 liters of hydrogen (at STP) are also produced? Zn + 2HCl  ZnCl2 + H kJ

19 Volume of H2  Moles of H2  Heat of reaction
Zn HCl  ZnCl H kJ Volume of H2  Moles of H2  Heat of reaction

20 Example #5: According to the following thermochemical equation for the combustion of glucose, (a) how many kilojoules of energy will be released when 12.5 g of glucose are combusted? (b) How many grams of glucose are needed to produce 3245 kJ of energy? C6H12O6 + 6O2  6CO2 + 6H2O kJ

21 C6H12O6 + 6O2  6CO2 + 6H2O kJ (a) How many kilojoules of energy will be released when 12.5 g of glucose are combusted?

22 C6H12O6 + 6O2  6CO2 + 6H2O kJ (b) How many grams of glucose are needed to produce 3245 kJ of energy?


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