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NOTES: - Thermochemical Equations (17.2)
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ENTHALPY ENTHALPY = a type of chemical energy, sometimes referred to as “heat content” Many reactions involve the production or absorption of heat. This heat is called the heat of reaction, or enthalpy (H). Example: CH O2 CO H2O kJ Heat Term
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Heat can be a product… When the heat is a product, it appears on the RIGHT side of the equation, and the reaction is said to be EXOTHERMIC. 2Mg + O2 2MgO + Heat
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Heat can also be a reactant….
When the heat is a reactant, it appears on the LEFT side of the equation, and the equation is said to be ENDOTHERMIC. NH4NO3 + Heat NH4+ + NO3-
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H = -333 kcal (why negative?)
An equation involving heat can be written 2 ways: CH4 + O2 H2O + CO kcal -or- CH4 + O2 H2O + CO2 H = -333 kcal (why negative?)
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Reaction Diagram: Exothermic
Change of Heat (H) Energy Exothermic Reaction (H = -)
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Reaction Diagram: Endothermic
Change of Heat (H) Energy Endothermic Reaction (H = +)
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REVIEW: Exo vs. Endothermic
exothermic reactions: q = ΔH < 0 (negative values) surroundings get hot heat appears on the right side of the equation (as a product)
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REVIEW: Exo vs. Endothermic
endothermic reactions: q = ΔH > 0 (positive values) surroundings get cold heat appears on the left side of the equation (as a reactant)
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Thermochemical Equations
● A chemical equation that shows the enthalpy (H) is a thermochemical equation. Example: 2H2(g) + O2(g) 2H2O(g) ∆H = -572 kJ
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Rules of Thermochemistry
Rule #1 - The magnitude of H is directly proportional to the amount of reactant of product.
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Rules of Thermochemistry
Example 1: H2 + Cl2 2HCl H = kJ Calculate H when 1.00 g of Cl2 reacts.
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H Cl2 HCl kJ ΔH = kJ (exothermic)
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Rules of Thermochemistry
Example 2: When an ice cube weighing 24.6 g of ice melts, it absorbs 8.19 kJ of heat. Calculate H when 1.0 mol of ice melts.
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H2O(s) kJ H2O(l)
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Rules of Thermochemistry
Example 3: Methanol burns to produce carbon dioxide and water: 2CH3OH + 3O2 2CO2 + 4H2O kJ What mass of methanol is needed to produce 1820 kJ?
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2CH3OH + 3O2 CO2 + H2O kJ
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Rules of Thermochemistry
Example 4: How much heat is produced when 58.0 liters of hydrogen (at STP) are also produced? Zn + 2HCl ZnCl2 + H kJ
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Volume of H2 Moles of H2 Heat of reaction
Zn HCl ZnCl H kJ Volume of H2 Moles of H2 Heat of reaction
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Example #5: According to the following thermochemical equation for the combustion of glucose, (a) how many kilojoules of energy will be released when 12.5 g of glucose are combusted? (b) How many grams of glucose are needed to produce 3245 kJ of energy? C6H12O6 + 6O2 6CO2 + 6H2O kJ
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C6H12O6 + 6O2 6CO2 + 6H2O kJ (a) How many kilojoules of energy will be released when 12.5 g of glucose are combusted?
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C6H12O6 + 6O2 6CO2 + 6H2O kJ (b) How many grams of glucose are needed to produce 3245 kJ of energy?
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