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IB physics Lab 5 follow-up
And you
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Proof that the F =. M (a)
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Your lab set-up ∑F = ∑ m X a Fm2g = M1 + m2 X. a + Fn - + Ffr = 0 M1
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Your lab set-up in a linear form
Break it into 2 separate systems ∑Fy 1 = 0 = fn – Fm1g ∑Fy 2 = 0 = fn – Fm2g ∑FX 1 = m1 a = Ft – Ffr ∑FX 2 = m2 a = F app - Ft Ft = Ft a = a * 2 common unknown variables !! + Fn + Fn + - - Ft Ft + Ffr = 0 F app (= Fm2g) M1 m2 - Fm1g Fm2g -
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THINK MAD SUBSTUTION!!!! NO way –
∑FX 1 = m1 a = Ft – Ffr ∑FX 2 = m2 a = F app - Ft Define Ft in terms of a in one equation and sub into the second equation!!! Ft = F app – m2 a ∑FX 1 = m1 a = F app – m2 a – Ffr Ffr = 0 here so eliminate from equation m1 a = F app – m2 a F app = (m1 + m2) a a = F app m1 + m2 NO way – Way!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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