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12-2 Arcs and Chords Holt McDougal Geometry Holt Geometry
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Learning Targets I will apply properties of arcs and chords.
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Vocabulary central angle semicircle arc adjacent arcs
minor arc congruent arcs major arc
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A central angle is an angle whose vertex is the center of a circle
A central angle is an angle whose vertex is the center of a circle. An arc is an unbroken part of a circle consisting of two points called the endpoints and all the points on the circle between them.
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Writing Math Minor arcs are named by the two endpoints of the arc. Major arcs and semicircles must be named by three points, with the endpoints being the first and third points named.
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Example 1: Data Application
The circle graph shows the types of grass planted in the yards of one neighborhood. Find mKLF. mKLF = 360° – mKJF mKJF = 0.35(360) = 126 mKLF = 360° – 126° = 234
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Check It Out! Example 1 Use the graph to find each of the following. a. mFMC mFMC = 0.30(360) = 108 Central is 30% of the . b. mAHB = 360° – mAMB c. mEMD = 0.10(360) mAHB = 360° – 0.25(360) = 36 = 270 Central is 10% of the .
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Adjacent arcs are arcs of the same circle that intersect at exactly one point. RS and ST are adjacent arcs.
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Example 2: Using the Arc Addition Postulate
Find mBD. mBC = 97.4 Vert. s Thm. mCFD = 180 – (97.4 + 52) = 30.6 ∆ Sum Thm. mCD = 30.6 mCFD = 30.6 mBD = mBC + mCD Arc Add. Post. = 97.4 Substitute. Simplify. = 128
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Check It Out! Example 2a Find each measure. mJNL 180° + 40° = 220°
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Check It Out! Example 2b Find each measure. mLJN mLJN = 360° – ( )° = 295°
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Within a circle or congruent circles, congruent arcs are two arcs that have the same measure. In the figure ST UV.
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Example 3A: Applying Congruent Angles, Arcs, and Chords
TV WS. Find mWS. TV WS chords have arcs. mTV = mWS Def. of arcs 9n – 11 = 7n + 11 Substitute the given measures. 2n = 22 Subtract 7n and add 11 to both sides. n = 11 Divide both sides by 2. mWS = 7(11) + 11 Substitute 11 for n. = 88° Simplify.
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Example 3B: Applying Congruent Angles, Arcs, and Chords
C J, and mGCD mNJM. Find NM. GCD NJM GD NM arcs have chords. GD NM GD = NM Def. of chords
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Example 3B Continued C J, and mGCD mNJM. Find NM. 14t – 26 = 5t + 1 9t = 27 t = 3 NM = 5(3) + 1 = 16
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Check It Out! Example 3a PT bisects RPS. Find RT. RPT SPT mRT mTS RT = TS 6x = 20 – 4x 10x = 20 x = 2 RT = 6(2) RT = 12
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Check It Out! Example 3b Find each measure. A B, and CD EF. Find mCD. mCD = mEF 25y = (30y – 20) 20 = 5y 4 = y CD = 25(4) mCD = 100
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Example 4: Using Radii and Chords
Find NP. Step 1 Draw radius RN. RN = 17 Step 2 Use the Pythagorean Theorem. SN2 + RS2 = RN2 SN = 172 SN2 = 225 SN = 15 Step 3 Find NP. NP = 2(15) = 30
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HOMEWORK: Pg 806, #5 – 18.
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