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Writing equations of circles in vertex form

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Presentation on theme: "Writing equations of circles in vertex form"β€” Presentation transcript:

1 Writing equations of circles in vertex form
MM3G2

2 Write the equation for the circle in vertex form:
Example 1 π‘₯ 2 + 𝑦 2 +2π‘₯βˆ’4π‘¦βˆ’4=0 Step 1: Move the constant to the other side of the equation & put your common variables together π‘₯ 2 +2π‘₯+ 𝑦 2 βˆ’4π‘¦βˆ’4+4=0+4 π‘₯ 2 +2π‘₯+ 𝑦 2 βˆ’4𝑦=4

3 Example 1 π‘₯ 2 +2π‘₯+ 𝑦 2 βˆ’4𝑦=4 Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 1 so divide everything by 1 π‘₯ 2 +2π‘₯+ 𝑦 2 βˆ’4𝑦=4 1

4 Example 1 π‘₯ 2 +2π‘₯+ 𝑦 2 βˆ’4𝑦=4 Step 3: Group the x terms together and the y terms together using parenthesis. (π‘₯ 2 + 2π‘₯ )+ 𝑦 2 βˆ’4𝑦 =4

5 Example 1 Step 4: Complete the square for the x terms
(π‘₯ 2 + 2π‘₯ )+ 𝑦 2 βˆ’4𝑦 =4 Step 4: Complete the square for the x terms Then for the y terms (π‘₯ 2 +2π‘₯ +1)+ 𝑦 2 βˆ’4𝑦 +4 =4+1+4 (π‘₯ 2 + 2π‘₯ +1)+ 𝑦 2 βˆ’4𝑦 +4 =9 2 2 =1 βˆ’4 2 =βˆ’2 12 =1 (βˆ’2)2 = 4

6 What is the center of this circle?
Example 1 (π‘₯ 2 + 2π‘₯ +1)+ 𝑦 2 βˆ’4𝑦 +4 =9 Step 5: Write the factored form for the groups. (π‘₯+1) 2 + π‘¦βˆ’2 2 =9 What is the center of this circle? (βˆ’1, 2) What is the radius? π‘Ÿ=3

7 Write the equation for the circle in vertex form:
Example 2 2π‘₯ 2 + 2𝑦 2 +12π‘₯+8𝑦+4=28 Step 1: Move the constant to the other side of the equation & put your common variables together 2π‘₯ 2 +12π‘₯+ 2𝑦 2 +8𝑦+4βˆ’4=28βˆ’4 2π‘₯ 2 +12π‘₯+ 2𝑦 2 +8𝑦=24

8 Example 2 π‘₯ 2 +6π‘₯+ 𝑦 2 +4𝑦=12 2π‘₯ 2 +12π‘₯+ 2𝑦 2 +8𝑦=24
Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 2 so divide everything by 2 2π‘₯ 2 +12π‘₯+ 2𝑦 2 +8𝑦=24 2 π‘₯ 2 +6π‘₯+ 𝑦 2 +4𝑦=12

9 Example 2 π‘₯ 2 +6π‘₯+ 𝑦 2 +4𝑦=12 Step 3: Group the x terms together and the y terms together using parenthesis. (π‘₯ 2 +6π‘₯ )+ 𝑦 2 +4𝑦 =12

10 Example 2 Step 4: Complete the square for the x terms
(π‘₯ 2 +6π‘₯ )+ 𝑦 2 +4𝑦 =12 Step 4: Complete the square for the x terms Then for the y terms (π‘₯ 2 +6π‘₯ +9)+ 𝑦 2 +4𝑦 +4 =12+9+4 (π‘₯ 2 +6π‘₯ +9)+ 𝑦 2 +4𝑦 +4 =25 6 2 = 3 4 2 = 2 32 = 9 22 = 4

11 What is the center of this circle?
Example 2 (π‘₯ 2 +6π‘₯+9)+ 𝑦 2 +4𝑦 +4 =25 Step 5: Write the factored form for the groups. (π‘₯+3) 2 + 𝑦+2 2 =25 What is the center of this circle? (βˆ’3, βˆ’2) What is the radius? π‘Ÿ=5

12 Write the equation for the circle in vertex form:
Example 3 4π‘₯ 2 +4 𝑦 2 +24π‘₯+32𝑦+13=157 Step 1: Move the constant to the other side of the equation & put your common variables together 4π‘₯ 2 +24π‘₯+4 𝑦 2 +32𝑦+13βˆ’13=157βˆ’13 4π‘₯ 2 +24π‘₯+4 𝑦 2 +32𝑦=144

13 Example 3 4π‘₯ 2 +24π‘₯+4 𝑦 2 +32𝑦=144 Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 4 so divide everything by 4 4π‘₯ 2 +24π‘₯+4 𝑦 2 +32𝑦=144 4 π‘₯ 2 +6π‘₯+ 𝑦 2 +8𝑦=36

14 Example 3 π‘₯ 2 +6π‘₯+ 𝑦 2 +8𝑦=36 Step 3: Group the x terms together and the y terms together using parenthesis. ( π‘₯ 2 +6π‘₯ )+( 𝑦 2 +8𝑦 )=36

15 Example 3 Step 4: Complete the square for the x terms
( π‘₯ 2 +6π‘₯ )+( 𝑦 2 +8𝑦 )=36 Step 4: Complete the square for the x terms Then for the y terms (π‘₯ 2 +6π‘₯ +9)+ 𝑦 2 +8𝑦 +16 = π‘₯ 2 +6π‘₯+9 + 𝑦 2 +8𝑦+16 =61 6 2 = 3 8 2 =4 32 = 9 42 =16

16 What is the center of this circle?
Example 3 π‘₯ 2 +6π‘₯+9 + 𝑦 2 +8𝑦+16 =61 Step 5: Write the factored form for the groups. π‘₯ 𝑦+4 2 =61 What is the center of this circle? (βˆ’3, 4) What is the radius? π‘Ÿ= 61

17 Write the equation for the circle in vertex form:
Example 4 5π‘₯ 2 +5 𝑦 2 βˆ’80π‘₯+20π‘¦βˆ’34=106 Step 1: Move the constant to the other side of the equation & put your common variables together 5π‘₯ 2 βˆ’80π‘₯+5 𝑦 2 +20π‘¦βˆ’34+34=106+34 5π‘₯ 2 βˆ’80π‘₯+5 𝑦 2 +20𝑦=140

18 Example 4 5π‘₯ 2 βˆ’80π‘₯+5 𝑦 2 +20𝑦=140 Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 5 so divide everything by 5 5π‘₯ 2 βˆ’80π‘₯+5 𝑦 2 +20𝑦=140 5 π‘₯ 2 βˆ’16π‘₯+ 𝑦 2 +4𝑦=28

19 Example 4 π‘₯ 2 βˆ’16π‘₯+ 𝑦 2 +4𝑦=28 Step 3: Group the x terms together and the y terms together using parenthesis. ( π‘₯ 2 βˆ’16π‘₯ )+( 𝑦 2 +4𝑦 )=28

20 Example 4 Step 4: Complete the square for the x terms
(π‘₯ 2 βˆ’ 16π‘₯ )+ 𝑦 2 +4𝑦 =28 Step 4: Complete the square for the x terms Then for the y terms (π‘₯ 2 βˆ’16π‘₯+64)+ 𝑦 2 +4𝑦 +4 = π‘₯ 2 βˆ’16π‘₯ 𝑦 2 +4𝑦+4 =96 βˆ’16 2 =βˆ’8 4 2 = 2 (βˆ’ 8) 2 =64 22 = 4

21 What is the center of this circle?
Example 4 π‘₯ 2 βˆ’16π‘₯ 𝑦 2 +4𝑦+4 =96 Step 5: Write the factored form for the groups. π‘₯βˆ’ 𝑦+2 2 =96 What is the center of this circle? (8,βˆ’2) What is the radius? π‘Ÿ= 96

22 What is the center of this circle?
You Try! Write the following equation of a circle in vertex form: 4π‘₯ 2 +4 𝑦 2 +8π‘₯βˆ’24𝑦+4=0 What is the center of this circle? What is the radius?


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