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Writing equations of circles in vertex form
MM3G2
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Write the equation for the circle in vertex form:
Example 1 π₯ 2 + π¦ 2 +2π₯β4π¦β4=0 Step 1: Move the constant to the other side of the equation & put your common variables together π₯ 2 +2π₯+ π¦ 2 β4π¦β4+4=0+4 π₯ 2 +2π₯+ π¦ 2 β4π¦=4
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Example 1 π₯ 2 +2π₯+ π¦ 2 β4π¦=4 Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 1 so divide everything by 1 π₯ 2 +2π₯+ π¦ 2 β4π¦=4 1
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Example 1 π₯ 2 +2π₯+ π¦ 2 β4π¦=4 Step 3: Group the x terms together and the y terms together using parenthesis. (π₯ 2 + 2π₯ )+ π¦ 2 β4π¦ =4
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Example 1 Step 4: Complete the square for the x terms
(π₯ 2 + 2π₯ )+ π¦ 2 β4π¦ =4 Step 4: Complete the square for the x terms Then for the y terms (π₯ 2 +2π₯ +1)+ π¦ 2 β4π¦ +4 =4+1+4 (π₯ 2 + 2π₯ +1)+ π¦ 2 β4π¦ +4 =9 2 2 =1 β4 2 =β2 12 =1 (β2)2 = 4
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What is the center of this circle?
Example 1 (π₯ 2 + 2π₯ +1)+ π¦ 2 β4π¦ +4 =9 Step 5: Write the factored form for the groups. (π₯+1) 2 + π¦β2 2 =9 What is the center of this circle? (β1, 2) What is the radius? π=3
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Write the equation for the circle in vertex form:
Example 2 2π₯ 2 + 2π¦ 2 +12π₯+8π¦+4=28 Step 1: Move the constant to the other side of the equation & put your common variables together 2π₯ 2 +12π₯+ 2π¦ 2 +8π¦+4β4=28β4 2π₯ 2 +12π₯+ 2π¦ 2 +8π¦=24
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Example 2 π₯ 2 +6π₯+ π¦ 2 +4π¦=12 2π₯ 2 +12π₯+ 2π¦ 2 +8π¦=24
Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 2 so divide everything by 2 2π₯ 2 +12π₯+ 2π¦ 2 +8π¦=24 2 π₯ 2 +6π₯+ π¦ 2 +4π¦=12
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Example 2 π₯ 2 +6π₯+ π¦ 2 +4π¦=12 Step 3: Group the x terms together and the y terms together using parenthesis. (π₯ 2 +6π₯ )+ π¦ 2 +4π¦ =12
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Example 2 Step 4: Complete the square for the x terms
(π₯ 2 +6π₯ )+ π¦ 2 +4π¦ =12 Step 4: Complete the square for the x terms Then for the y terms (π₯ 2 +6π₯ +9)+ π¦ 2 +4π¦ +4 =12+9+4 (π₯ 2 +6π₯ +9)+ π¦ 2 +4π¦ +4 =25 6 2 = 3 4 2 = 2 32 = 9 22 = 4
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What is the center of this circle?
Example 2 (π₯ 2 +6π₯+9)+ π¦ 2 +4π¦ +4 =25 Step 5: Write the factored form for the groups. (π₯+3) 2 + π¦+2 2 =25 What is the center of this circle? (β3, β2) What is the radius? π=5
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Write the equation for the circle in vertex form:
Example 3 4π₯ 2 +4 π¦ 2 +24π₯+32π¦+13=157 Step 1: Move the constant to the other side of the equation & put your common variables together 4π₯ 2 +24π₯+4 π¦ 2 +32π¦+13β13=157β13 4π₯ 2 +24π₯+4 π¦ 2 +32π¦=144
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Example 3 4π₯ 2 +24π₯+4 π¦ 2 +32π¦=144 Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 4 so divide everything by 4 4π₯ 2 +24π₯+4 π¦ 2 +32π¦=144 4 π₯ 2 +6π₯+ π¦ 2 +8π¦=36
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Example 3 π₯ 2 +6π₯+ π¦ 2 +8π¦=36 Step 3: Group the x terms together and the y terms together using parenthesis. ( π₯ 2 +6π₯ )+( π¦ 2 +8π¦ )=36
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Example 3 Step 4: Complete the square for the x terms
( π₯ 2 +6π₯ )+( π¦ 2 +8π¦ )=36 Step 4: Complete the square for the x terms Then for the y terms (π₯ 2 +6π₯ +9)+ π¦ 2 +8π¦ +16 = π₯ 2 +6π₯+9 + π¦ 2 +8π¦+16 =61 6 2 = 3 8 2 =4 32 = 9 42 =16
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What is the center of this circle?
Example 3 π₯ 2 +6π₯+9 + π¦ 2 +8π¦+16 =61 Step 5: Write the factored form for the groups. π₯ π¦+4 2 =61 What is the center of this circle? (β3, 4) What is the radius? π= 61
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Write the equation for the circle in vertex form:
Example 4 5π₯ 2 +5 π¦ 2 β80π₯+20π¦β34=106 Step 1: Move the constant to the other side of the equation & put your common variables together 5π₯ 2 β80π₯+5 π¦ 2 +20π¦β34+34=106+34 5π₯ 2 β80π₯+5 π¦ 2 +20π¦=140
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Example 4 5π₯ 2 β80π₯+5 π¦ 2 +20π¦=140 Step 2: Identify the coefficients of the squared terms and divide everything by that coefficient. Both coefficients are 5 so divide everything by 5 5π₯ 2 β80π₯+5 π¦ 2 +20π¦=140 5 π₯ 2 β16π₯+ π¦ 2 +4π¦=28
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Example 4 π₯ 2 β16π₯+ π¦ 2 +4π¦=28 Step 3: Group the x terms together and the y terms together using parenthesis. ( π₯ 2 β16π₯ )+( π¦ 2 +4π¦ )=28
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Example 4 Step 4: Complete the square for the x terms
(π₯ 2 β 16π₯ )+ π¦ 2 +4π¦ =28 Step 4: Complete the square for the x terms Then for the y terms (π₯ 2 β16π₯+64)+ π¦ 2 +4π¦ +4 = π₯ 2 β16π₯ π¦ 2 +4π¦+4 =96 β16 2 =β8 4 2 = 2 (β 8) 2 =64 22 = 4
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What is the center of this circle?
Example 4 π₯ 2 β16π₯ π¦ 2 +4π¦+4 =96 Step 5: Write the factored form for the groups. π₯β π¦+2 2 =96 What is the center of this circle? (8,β2) What is the radius? π= 96
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What is the center of this circle?
You Try! Write the following equation of a circle in vertex form: 4π₯ 2 +4 π¦ 2 +8π₯β24π¦+4=0 What is the center of this circle? What is the radius?
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