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Monitoring the Environment

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Presentation on theme: "Monitoring the Environment"— Presentation transcript:

1 Monitoring the Environment
Global Warming

2 Natural Greenhouse Effect
The Earth’s surface absorbs short-wave radiation from the sun (visible light and UV rays), which is then re-emitted as long wave infra-red (IR) radiation. Some gases in the atmosphere trap part of this IR radiation, thereby warming the Earth’s atmosphere. These gases are referred to as greenhouse gases. Common greenhouse gases include CO2, H2O and CH4 (methane). Their polar covalent bonds stretch and bend to absorb the IR radiation.  The mechanism by which these gases maintain a temperature in the Earth’s atmosphere that can support life is known as the Natural Greenhouse Effect

3 Enhanced Greenhouse Effect
Human activities affect the concentration of certain greenhouse gases They therefore have the potential to disrupt the thermal equilibrium of the atmosphere. An increase in the concentration of greenhouse gases in the atmosphere trap a greater amount of IR radiation. The net result is that the temperature of the Earth’s atmosphere is raised. This is known as the enhanced greenhouse effect.

4 Enhanced Greenhouse Effect
Cause Burning carbon based fuels Deforestation Agriculture – rice paddies, cows, sheep, natural gas fields, industrial activities, garbage dumps Effect Increased CO2 Emissions Decreased CO2 conversion via photosynthesis Increased CH4 emissions

5 Predicted Effects Increase in global temperature
Rise in sea levels due to water expansion at higher temperatures Disruption of ecosystems Climate change and shift in weather patterns Melting polar ice caps

6 Possible Solutions Plant more trees Reduce emissions
Burn less carbon-based fuels Use alternative energy sources Capture and storage of CO2 emissions

7 Ocean Acidification As well as liquids and solids, gases can also be soluble in water. Oxygen for example is soluble in water and is vital for the survival of aquatic plants and animals. Carbon dioxide is also soluble in water. CO2(g) ⇌ CO2(aq) As the concentration of carbon dioxide in the atmosphere increases, so too will the dissolved carbon dioxide content.

8 Oxides Carbon dioxide is a non-metal oxide.
Non-metal oxides are acidic CO2(aq) + H2O(l) -> Carbon dioxide + water goes to carbonic acid

9 Acids and Bases Review Acids are proton donors
Bases are proton acceptors Acids ionise when dissolved in water H2CO3 + H2O -> pH = -log[H+] [H+] = 10-pH The skeletons and shells of many marine organisms are made of calcium carbonate H+ + CaCO3 ->

10 Monitoring the Environment
Photochemical Smog

11 Oxides of Nitrogen Nitrogen comprises 78% by volume of the atmosphere. It exists as stable triple covalently bonded N2 molecules and is chemically very stable. High temperature furnaces and combustion engines can provide the large amount of activation energy required to break the N2 triple bonds N2(g) + O2(g) → 2NO(g) NO can then further react with oxygen to form nitrogen dioxide 2NO(g) + O2(g) → 2NO2(g) Oxides of nitrogen are harmful to both animal and plant life They are also a major contributor to acid rain

12 Photochemical Smog Photochemical smog is a special kind of smog caused by pollutants Primary pollutants are chemicals released directly into the environment from human activity Examples include NO, CO, CO2 and unburnt hydrocarbons known as volatile organic compounds (VOC’s) Secondary pollutants are formed by reactions of primary pollutants with air, water or sunlight Examples include NO2, O3 and other organic compounds

13 Photochemical Smog Formation of photochemical smog is favoured by certain weather conditions, eg windless sunny days Temperature inversion can lead to smog being trapped Temperature inversion begins on calm clear nights when the Earths surface rapidly cools The air near the ground then becomes cooler than the air above This colder, denser layer then traps any smog formed during the day, giving more time for primary pollutants to react This can last for several days until broken up by winds

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15 Formation of Ozone Ozone is considered a pollutant when formed in the troposphere Ozone causes yellowing of plant leaves and a reduction of photosynthesis Ozone is a respiratory irritant, causing coughing and restriction of airways It also causes rubber to harden and crack, affecting rubber seals Ozone is formed when intense sunlight and high concentrations of NO2 are found Sunlight splits an oxygen atom from the NO2 to form NO and a highly reactive oxygen atom NO2  NO + O The oxygen atom then reacts with oxygen gas to from ozone O O2  O3

16 Photochemical Smog The concentration of primary pollutants generally rises sharply during peak morning traffic The peak concentration of secondary pollutants generally occurs later in the day as the primary pollutants are converted by sunlight The peak concentration of ozone then occurs during the afternoon

17 Catalytic Converters Catalytic converters can reduce the amount of pollutants coming from a cars exhaust They have a simple design, but are expensive due to the catalyst metals required (often an alloy of platinum and rhodium) The platinum speeds up reactions with oxygen CO and unburnt hydrocarbons produced from incomplete combustion are oxidised Rhodium helps to convert NO into nitrogen and CO2 2CO(g) NO(g)  N2(g) CO2(g) 2NO(g) H2(g) N2(g) H2O(g)

18 Monitoring the Environment
Analytical Chemistry

19 Mole Amount of a substance
A way to compare amounts of substances that react The number of particles in g of carbon-12 Equivalent to Avagadro’s Number: 6.02 x 1023

20 Molar Mass Can be derived from the periodic table
4 significant figures m = n M n = m / M M = m / n Units of g mol-1

21 Significant Figures Final answer to contain the same number of significant figures as least precise piece of data Do not round until final answer Count from first non zero digit With a decimal point, zeros at the end count Without a decimal point zeros at the end do not count

22 Supportive Questions Calculate the number of moles in 2.2g of CO2
m = n M n = m / M n = 2.2 / ( x 2) n = mol (2 sf)

23 Supportive Questions Calculate the mass of 0.200 mol of Na2CO3.
m = n M m = x (22.99 x x 3) g 21.2 g (3sf)

24 Concentration Concentration can be described using many different standard conventions. In general it is: 𝑎𝑚𝑜𝑢𝑛𝑡 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒 𝑎𝑚𝑜𝑢𝑛𝑡 𝑜𝑓 𝑠𝑜𝑙𝑣𝑒𝑛𝑡 We can use the units of the concentration to determine what the units of the solute and solvent should be. Some common units of concentration are mol L-1 and g L-1.

25 Concentration mol L-1 (moles per litre) = n (moles) / V (litres)
g L-1 (grams per litre) = mass (grams) / V (litres) % w/v (percent weight per volume) = mass (grams) / 100 mL ppm (mg L-1) (parts per million) = mass (milligrams, mg) / V (litres) ppb (g L-1) (parts per billion) = mass (micrograms, g) / V (litres)

26 Molar Concentration Concentration involving moles is also referred to as molarity Molar concentration (C) measures in mol L-1 C = n / v You will occasionally see molarity written using M, eg 0.2M is equivalent to 0.2 mol L-1

27 Supportive Questions 2 Calculate the molarity when 0.20 mol of HCl is dissolved in ml of water. C = n / v C = 0.2 / 0.5 C = 0.40 mol L-1

28 Concentration mol L-1 ppm g L-1 ppb %w/v
The concentration conversion table: know it, love it mol L-1 ppm x1000 xM g L-1 x1000 x10 x106 ppb %w/v Hint: moving left you divide, moving right you multiply

29 Mole Ratios A balanced equation provides the mole ratios of the substances that react or are produced during a reaction We can use these ratios to calculate unknown quantities The relative amounts (in moles) of substances reacting or produced during a reaction are indicated by the coefficients in the balanced equation for the reaction

30 Supportive Questions 3 Complete combustion of propanol
C3H7OH(g) O2(g) CO2(g) H2O(g) Propanol : Oxygen = 1:4½ or 2:9 Propanol : Carbon dioxide = 1:3

31 Supportive Questions 3 m = n M n = m / M
n = 220 / (12.01 x x ) n = 3.66 mol 𝑛 ( 𝑂 2 ) 𝑛 ( 𝐶 3 𝐻 7 𝑂𝐻) = n = 4.5 x 3.66 n = mol m = x (16 x 2) m = g m = 530 g (2sf)

32 Titration A titration is a technique that enables a chemist to measure the concentration of a substance in a solution. It involves using glassware that is calibrated for an exact volume. This volumetric analysis, involving a titration is a quantitative analysis because it involves finding the amount of a substance in a solution There are 3 practical tasks associated with titrations preparation of the solutions preparation of the glassware performing the titration

33 Rinsing Rinsing of the apparatus is important to ensure accurate and precise results With each apparatus, we either want to control the concentration or the number of moles To control the moles no more can be unknowingly added Hence final rinse is with distilled water To control the concentration, it cannot be diluted Hence final rinse is with the solution about to be used

34 Rinsing Volumetric flask and Conical Flask Pipette and Burette
Rinse with distilled water Need to control moles of substance Pipette and Burette First rinse with distilled water Final rinse with solution they will contain Need to control the concentration of substance

35 Volumetric Flask Weigh mass of solute on watch glass
Transfer to flask using dry funnel Wash watch glass and funnel a number of time into flask Half fill flask with water and swirl to dissolve Add further water until level with meniscus DO NOT overshoot the meniscus – you will have to start again!

36 Techniques: Pipette Pipette should be held vertically
Fill so bottom of meniscus is at etched line – check at eye level When draining, hold against the side of flask and allow to drain – don’t shake to remove last drop

37 Techniques: Burette Burettes do not need to be refilled between titrations Make sure to remove air bubbles, droplets on the side and the funnel Use left hand turn – right hand swirl technique Endpoint should be approached drop wise Use wash bottle to ensure any liquid that leaves the burette reaches the reaction liquid

38 Monitoring the Environment
Chromatography

39 Chromotography

40 Chromatography All forms of chromatography involve a mobile phase passing over a stationary phase Chromatography separates different components by way of their different attraction to the mobile and stationary phase The strength of this attraction is due to their relative polarities Polar substances will adsorb onto the more polar phase

41 Polarity Revision “Like dissolves like” – a good reminder, but never an answer to a question! Polar bonds are caused by differing electronegativities causing uneven sharing of electrons Polar molecules are asymmetrical molecules that contain polar bonds Polar bonds attract each other via electrostatic interactions

42 Phase Interactions If the mobile phase is polar:
The more polar chemical will adsorb more strongly to the mobile phase, and so will travel the furthest (in paper/TLC) and exit earlier (column/HPLC/GC) Larger Rf and shorter retention time If the stationary phase is polar The more polar chemical will adsorb more strongly to the stationary phase, and so will travel the least distance (paper/TLC) and exit later (column/HPLC/GC) Smaller Rf and longer retention time

43 Retardation Factor Retardation Factor (Rf) is a measure of how far the solute travels relative to the solvent front This enables comparisons between experiments Rf = distance moved by solute distance moved by solvent Rf is dimensionless and always less than 1 (usually as a decimal)

44 Atomic Absorption Spectroscopy

45 Energy Levels Electrons exist in specific shells of varying energy
Each shell has subshells, each with their own level of energy Subshells are S, P, D and F The subshells can hold increasing numbers of electrons S can hold 2 P can hold 6 D can hold 10 F can hold 14

46 Naming Subshells 2p4 The 2 signifies the number of the main energy level The p signifies the subshell The 4 shows that there are 4 electrons in this subshell

47 Filling Subshells Subshells will fill in order of energy levels
Eg Fe: 1s2 2s2 2p6 3s2 3p6 4s2 3d6

48 Exceptions Copper and Chromium do not exactly conform to these rules
Both have only 1 4s electron to gain a full and half full d shell respectively Cr: 1s2 2s2 2p6 3s2 3p6 4s1 3d5 Cu: 1s2 2s2 2p6 3s2 3p6 4s1 3d10

49 Ions For ions we simply add or subtract electrons equivalent to the charge on the ion Always take electrons from the outer shell, which is not always necessarily the last one written down Eg Na+: 1s2 2s2 2p6 3s1 F- : 1s2 2s2 2p6 3s2 Fe2+: 1s2 2s2 2p6 3s2 3p6 4s2 3d6

50 Electron configuration and absorption of energy
Electrons exist in finite energy levels. The electronic configuration gives us the position of electrons in their ground state. This is their most stable configuration and is achieved at room temperature. An electron can absorb energy to move to a more excited state. They can do this in two ways: Absorb heat: absorbs energy equal to the energy gap between electron energy levels Absorb light: can only absorb the exact energy equal to the energy gap between electron levels

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52 Emission Spectrum Electrons are not stable in this excited state and quickly drop down, emitting a photon with the same energy as the corresponding energy gap between energy levels. As this is a specific amount of energy, it will have a specific wavelength and hence colour.

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55 Flame Test Qualitative test for metals in solution
Can also be used for coloured lights This emission of light is called an emission spectrum

56 AAS Involves the absorption of electromagnetic radiation of certain wavelengths A spectrophotometer measures the intensity of the radiation transmitted through the sample relative to the intensity entering Can therefore be used for quantitative measurements

57 AAS

58 AAS – radiation source Cathode lamp containing the metal to be analysed Emits radiation of certain frequencies that correspond to the energy gaps characteristic of the metal sample This means that impurities will not interfere with the measurements

59 AAS - flame The radiation is directed through a flame into which the sample is sprayed. Any metal atoms the same as the lamp will absorb the radiation emitted The absorbance is proportional to the concentration of metal in the sample

60 AAS – filter and detector
A filter or monochromator is used to select the frequency of light to pass through to the detector Allows AAS to be used with impure samples

61 Example Concentration Absorbance 2.0 0.051 4.0 0.097 6.0 0.148 8.0
0.201 10.0 0.253

62 Calibration Curve


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