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5-3 Unit 5 Trigonometry.

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Presentation on theme: "5-3 Unit 5 Trigonometry."— Presentation transcript:

1 5-3 Unit 5 Trigonometry

2 Solve the system of equations
Do Now 5-3 Solve the system of equations Essential Question: What is the hypotenuse of a triangle with a leg length of 5√3?

3 Agenda Partner Practice Exit Ticket Do Now Good Things!!! Notes
Intro to Unit 5 – Trigonometry Special Right Triangles Partner Practice Exit Ticket

4 Good Things!

5 Pythagorean Theorem Review
C is ALWAYS the hypotenuse!! If it doesn’t add up, it means you DON’T have a right triangle!

6 Pythagorean Theorem a. Find the value of x. Express your answer in simplest radical form. b. Is this a right triangle? Why or why not? 3 6 11 4 x 9

7 Notes: Special Right Triangles
Some right triangles have special relationships There are only TWO “special right triangles” Triangles Triangles

8 Notes: Triangles You know how to find any side length of a right triangle with the Pythagorean Theorem 1. We have a square with a side length of 2. What is the length of the diagonal? 2. We have a square with a side length of 6. What is the length of the diagonal? 2 6 If it’s a square, what will the new angle measures be?

9 Notes: Triangles 3. We have a square with a side length of 5. What is the length of the diagonal? 4. We have a square with a side length of 8. What is the length of the diagonal? 8 5 Notice a pattern?

10 Notes: 45-45-90 Triangles 7 Angle Measures 45° 90° Side Lengths a a√2
*draw in your notes Angle Measures 45° 90° Side Lengths a a√2 7

11 Using the Pythagorean Theorem, find the length of the missing side.
Notes: Triangles Using the Pythagorean Theorem, find the length of the missing side. 5. 90° 60° 30° 6. 90° 60° 30° 6 8 4 3

12 Using the Pythagorean Theorem, find the length of the missing side.
Notes: Triangles Using the Pythagorean Theorem, find the length of the missing side. 7. 90° 60° 30° 8. 90° 60° 30° 10 14 7 5

13 Notes: 30-60-90 Triangles 30° 60° 90° a a√3 2a Angle Measures
*draw in your notes Angle Measures 30° 60° 90° Side Lengths a a√3 2a

14 Special Right Triangles
Angle Measures 45° 45° 90° 30° 60° 90° Side Lengths a a a√2 a a√ a

15 Guided Practice 1 – Step by Step
Identify your angles Identify your side lengths -we are given a length x -we are given a hypotenuse 8 Solve for a 8 = a√2 *isolate a* 8/√2 = a *rationalize denominator* 8√2 / 2 = a 4√2 =a

16 Guided Practice 2 30 60 90 a a√ a What type of special right triangle is this? 2a = 6 c. a = x; a√3 = y d. Solve for a: a = 3, so x = 3 and y = 3√3

17 Partner Practice You have ~10 minutes to complete the 5 partner practice problems We will review them together before you begin the exit ticket

18 Exit Ticket


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