1. Lesson 6.10 Neutralization and Solution Stoichiometry Mrs. Wilson
Thurs 5-05 and Wed 5-11
Lesson 6.10 Neutralization and Solution Stoichiometry
Mrs. Wilson

2. Objectives Write neutralization equations for acid-base reactions.
Calculate the molarity of acetic acid in vinegar.
Solve solution stoichiometry problems.
Solve solution stoichiometry problems as related to the process of titration.
Homework:
Preparing Solutions Lab due Tuesday 5-09
Watch a video (I will send it out and post online) to prepare for the lab next class.
Lesson 6.10 homework + review questions not completed
Unit 6 Exam – Tuesday 5/17

3. HCl + NaOH  ______ + ______
Engage – Salty Water
When acids and bases react, they neutralize.
If the # of moles of acid and base are equal and there is no excess, the resulting pH will be 7.
HCl + NaOH  ______ + ______

5. Quick Lab: Molarity of Vinegar
Objective: Collect data to help you calculate the molarity of acetic acid (HC2H3O2) in vinegar. WARNING: Do not mix pipettes! Complete the Procedure, collect and record the data, and complete questions #1-2.

6. Quick Lab: Molarity of Vinegar
Question #3

7. 37.9 mL
1.83 M

8. 0.468 M
33 mL

9. Titration “Buret Rinsing Demo” video
Technique: Preparing the Buret for Titration
Rinse a clean buret several times with 5 mL portions of distilled water and then with portions of base.
Allow the titrant to drain through the stopcock so that the tip gets rinsed with titrant as well.
Discard the rinse solution in a waste beaker. Clamp the buret into place, and fill it with the base. Remove air bubbles from the tip of the buret and the stopcock by draining several milliliters of titrant. Dispose of the drained titrant in a waste beaker.
“Buret Rinsing Demo” video

10. Solving Titration Problems
Subtract the initial buret reading and the final buret reading.
You should know the buret solution
molarity. Calculate the # moles of
solute delivered to the flask.
Do solution stoichiometry to
determine the # moles and molarity
of the unknown solution in the
flask.

11. 0.042 M
0.42 M

12. Complete the Review questions on pgs 28-29.
Answers:
0.800 M KOH
(What is the molarity of the vinegar?) M
2.64 x 10-4 M
0.876 M