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Electrolysis predictions and half equations. 19/05/2019
Starter- Write the the name and formula and charge for each ion (the first is done for you) Anything in group 1 e.g. Sodium = Na+ 1+ Anything in group 2 e.g. Calcium = Anything in group 3 e.g. aluminum = Anything in group 6 e.g oxide Anything in group 7 e.g. iodide Hydrogen Ammonium Nitrate Hydroxide Hydrogen carbonate Sulfate Carbonate
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To make prediction of what will form at the anode and cathode
Electrolysis predictions and half equations. 19/05/2019 To make prediction of what will form at the anode and cathode To make good observations of what you see. To explain your observations by making links to theory To be able to write half equations for the reactions taking place at the anode and cathode.
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Electrolysis predictions
observation Conclusion Substance Anode Cathode
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What am I looking for ? What you observed. Colour, smell, bubbles-this will not always be what you excepted! Prediction-A description e.g. silver metal, orange metal fizzing, green gas, brown gas. Metal to cathode, non-metal to anode OR nothing ! If substance is covalent. prediction observation Conclusion Substance Anode Cathode Explanation- because e.g. no free moving ions, e.g. not what I excepted at the anode another reaction must be taking place.
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prediction observation Conclusion Substance Anode Cathode Ethanol Nothing it is covalent Light bulb did not light, it is covalent so no free moving ions or delocalized electrons. glucose NaCl (s) Nothing, ions are in a fixed position cannot move Light bulb did not light, ions are in a fixed position cannot move NaCl (aq) Green chlorine gas Silver sodium metal Anode-bubbles, smell of swimming pools. Cathode- bubbles! Dissolved ions are free to move, something else is happening at cathode
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prediction observation Conclusion Substance Anode Cathode H2SO4 SO2 ? SO3 and O2 ? H2 gas Light bulb light colorless gas at both electrodes. Need further testing to find out gases identity. CuSO4 (s) Nothing, ions are in a fixed position cannot move Light bulb did not light, ions are in a fixed position cannot move CuSO4 (aq) Orange metal formed on cathode Anode-bubbles, cathode coating of orange metal covers Cathode Dissolved ions are free to move, something else is happening at cathode
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write ionic half-equations representing the re actions at the electrodes during electrolysis
Electrons carry the current through the wire. Ions carry the current through the liquid
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1.54 write ionic half-equations representing the reactions at the electrodes during electrolysis
Ions become atoms or molecules By gaining or loosing electrons They “give” electrons to the circuit Or “take” electrons from the circuit To make the electricity flow.
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1.54 write ionic half-equations representing metal cations-easy
At the CATHODE Pb e- --> Pb Gains electrons So is reduced Cation
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At the ANODE Br - --> Br + 1e- Br - --> Br2 + 1e-
1.54 write ionic half-equations representing non-metal anions-a wee bit harder At the ANODE Br - --> Br + 1e- Br - --> Br2 + 1e- 2Br - --> Br2 + 2e- Loses electrons So is reduced anion
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Electrolysis Cations-positive ions (metals) go to the negative electrode –Cathode Metalx+(aq) + xe- ---> Metal (s) Anions negative ions (non-metal) go to the positive electrode-Anode. Non-metalx- (aq) ---> non-metal + xe- CAUTION WITH DIATOMIC MOLECULES
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= bromide ion = lead ion Anode Cathode 12
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O.I.L.R.I.G. Oxidation is loss of electrons
Reduction is gain of electrons 13
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A grade work = bromide ion At the cathode:
= lead ion At the cathode: Pb+ gains electrons to form lead metal. It is REDUCED. At the anode: Br- loses electrons to form bromine gas. It is OXIDISED. Anode Cathode A grade work 14
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Compound Anode Cathode Sodium Bromide Potassium Iodide Calcium Fluoride Magnesium Oxide Lithium Chloride
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Sodium Bromide Potassium Iodide Calcium Fluoride Magnesium Oxide
Half equations- ions on the left. Elements on the right. Add the correct number of electrons to the appropriate side so charges on both side balance Sodium Bromide Potassium Iodide Calcium Fluoride Magnesium Oxide Lithium Chloride 2Br > Br2 + 2e- Na e- --> Na
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