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The Distance and Midpoint Formulas

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1 The Distance and Midpoint Formulas
ALGEBRA 1 LESSON 11-3 pages 594–597  Exercises 1. 15 2. 14 3. 10 5. 2.8 6. 8.1 7. 16 9. (1, 6) 10. (–1, 12) 11. (0, 0) 22. MN ; NP ; MP = 5 23. JK = 4; KL ; LJ 24. TU ; UV ; VT 25. a. OR = , ST = b. ; c. yes 26. a. (20, 80), (–40, 30) b ft c. (–10, 55) or 55L10 12. (–2, 3) 13. 5, –5 14. – 2 , –1 15. (–4, 4) , –9 19. AB ; BC ; AC = 5 20. DE ; EF ; DF 21. RS ; ST ; RT 1 2 1 2 5 2 5 2 1 2 11-3

2 The Distance and Midpoint Formulas
ALGEBRA 1 LESSON 11-3 28. Check students’ work. 29. a. b. (0, – ) c. one half mile south of the substation 30. about 9.5 km apart 31. a mi b. 20 mi, 21.2 mi c. 15 min, 16 min 32. Yes; all sides are congruent. 27. Answers may vary. Sample: Suppose you have (1, 1) and (4, –3). To find the distance, square the difference between the x-coordinates. Square the difference between the y-coordinates. Find the sum and take the square root, so = 5. To find the midpoint, add x-coordinates together and divide by 2. Repeat for y-coordinates. So, 1 2 1 + 4 2 , 1 – 3 2 5 2 = , –1 11-3

3 The Distance and Midpoint Formulas
ALGEBRA 1 LESSON 11-3 33. a. R(–27, –5) b. PR = RQ = 34. a. about 4.3 mi b. about 17.4 mi 35. a. M(–0.5, 3); N(5.5, 3) b. They are equal. 36. (x, y) 37. They are opposites. 38. a. 5 units b. Answers may vary. Sample: (5, 0), (0, 5), (–5, 0), (0, –5), (3, –4), (–3, 4), (–3, –4) c. circle 4 3 50. 26 52. 8 54. –14, 14 55. –10, 10 56. no solution 57. –5, 5 58. no solution 39. a. y = – x + 1 b. c. 3 40. Yes; the distance from each point to the center is 5. 42. 5 44. –5 45. 3 46. –8 9 5 7 5 , – 11-3

4 The Distance and Midpoint Formulas
ALGEBRA 1 LESSON 11-3 59. – , 60. k2 + 11k + 24 61. v2 + 2v – 35 62. 2p2 – 17p – 9 63. 8w4 + 19w2 + 11 64. 7t3 + 5t2 + 5t – 2 65. 6c3 – 27c2 + 33c + 24 2 3 2 3 11-3


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