1. Warm-up
If 45.0 mL of 2.50 M NaOH is needed to neutralize 36.0 mL of a HCl solution, what is the molarity of the acid?

2. Unit 10 Review Standard – 25 MC questions
Honors – 15 MC (60%), and 10 short answer (40%)

3. Topics Covered Solutions Acids & Bases Neutralization
Solution Stoichiometry
Don’t lose points because of units or sigfigs! 

4. Solutions
Vocabulary: Solute, Solvent, Saturated, unsaturated, supersaturated, dilute, concentrated, volumetric flask
Solubility curves
solubility unit: g/100g H2O
Read chart and adjust value if asked about a solution that is not 100 g of water
Colligative properties (BP & OP increase, FP & VP decrease) when a solute is added.
Molarity =mol of solute/liters of solution
Dilutions (M1V1 =M2V2)

5. Acids & Bases Neutralization Reactions & Metal-Acid Reaction
Properties of each
The 7 Strong acids
Strong bases
Strong acids and bases completely dissociate. Weak do not.
Identifying acids & base (Bronsted-Lowry/Arrhenius) and matching Conjugate Pairs

6. pH Scale pH equations (on reference sheet)
pH indicators (litmus paper)
Since Strong acids dissociate completely, [strong acid] = [H+]
Since Strong bases dissociate completely, [strong base] = [OH-]

7. Neutralization & Solution Stoichiometry
Vocabulary: titration, equivalence point, end point, titrant, analyte,
Titration curves
Neutralization calculations (titration) ***Must use Liters!!!!