1. Homework
Lesson 5.3_page 296 # ALL

2. Practice Problems
x2 – 16x + 15
x2 – 26x + 48

3. Factor by Grouping f(x)= 2x² – 7x – 15 2x² – 10x + 3x – 15 =0
-30
-10 3 -7
Note: you are on the right track because you have (x-5) in both parenthesis
2x(x – 5) + 3(x – 5) =0
(2x + 3)(x – 5)=0

4. Practice Problems f(x)= 3x2 – 16x – 12 f(x)= 4x2 + 5x – 6
Solutions:
a) (x-6)(3x+2)
(x+2)(4x-3)
(2x+7)(2x-7)
(x+4)(2x+3)
f(x)= 3x2 – 16x – 12
f(x)= 4x2 + 5x – 6
f(x)= 4x2 – 49
f(x)= 2x2 + 11X + 12

5. SHORTCUTS a2 + 2ab + b2 (a+b)2 a2 - 2ab + b2 (a - b)2
Example: 25x2 + 90x + 81
(5x+9)(5x+9) (5x + 9)2
a2 - 2ab + b (a - b)2
Example: 9x2 – 42x + 49
(3x-7)(3x-7) (3x – 7)2
a2 - b (a+b)(a - b)
Example: x2 – 64
(x + 8)(x – 8)

6. Zero-Product Property
Zero-Product Property: If pq= 0, then p = 0 or q = 0
ax2 + bx + c = 0 is called the general form of a quadratic equation

7. Example
given f(x) = x2 - 36, find the solution

8. Example
given 15x2 = 7x + 2, find the solution