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Ch. 7: Chemical Formulas and Compounds
7.4 Determining Chemical Formulas
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Empirical Formula formula containing the simplest whole-number ratio of atoms not necessarily the CORRECT molecular formula Why? Ex. BH3 and B2H6 have same empirical formula have different molecular formulas
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Calculating Empirical Formulas from Percent Composition
convert percentage to grams by assuming there is 100 g total of sample convert grams to moles for each element using molar mass identify the smallest mole value divide each mole value by that smallest value
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Example 1 Quantitative analysis shows that a compound contains 32.38% Na, 22.65% S, and 44.99% O. Find the empirical formula. Assuming you have 100 g of sample total 32.38 g Na 22.65 g S 44.99 g O
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Example 1 Na2SO4 sodium sulfate Convert each of those to moles
Divide by the smallest / ≈ 2 / ≈ 1 / ≈ 4 Na2SO4 sodium sulfate
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Calculating Empirical Formula from mass composition
don’t have to assume you have 100 g since you have an actual amount follow all other steps the same way
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Example 2 Analysis of a g sample of a compound containing only P and O, is known to contain g of P. Find the empirical formula. Find the mass of all components mtotal = mP + mO so mO = mtotal – mP mass of O : = 5.717g
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Example 2 P2O5 diphosphorus pentoxide
Convert all mass values to moles using molar mass Divide by the smallest mole value To get rid of the decimal, multiply by integer / ≈ 1 / ≈ 2.5 P2O5 diphosphorus pentoxide
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Molecular Formulas the molecular formula is the actual formula for a compound could be same as the empirical formula but doesn’t have to be same to find molecular formula: need empirical formula need actual molar mass (or formula mass) compare the molar mass of empirical formula to actual molar mass
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Example 3 In the last example the empirical formula was found to be P2O5. Experimentation shows that the molar mass is actually g/mol. Find the molecular formula.
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Example 3 Find molar mass of empirical formula
2( ) + 5( ) = Divide the actual molar mass by the empirical formula’s molar mass / ≈ 2 Multiply this number by each subscript in empirical formula P4O10
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