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Allometric relationships between knee cartilage volume, thickness, surface area and body dimensions
I.G. Otterness, Ph.D., M.-P.H. Le Graverand, M.D., Ph.D., F. Eckstein, M.D., Med. Osteoarthritis and Cartilage Volume 16, Issue 1, Pages (January 2008) DOI: /j.joca Copyright © 2007 Osteoarthritis Research Society International Terms and Conditions
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Fig. 1 Correlation of the VC of the knee with the tAB of the knee. The data were fit to the equation VC=a×tAB1.5 where a=0.0256, r2=0.86 and P< () Females, (●) Males. Osteoarthritis and Cartilage , 34-40DOI: ( /j.joca ) Copyright © 2007 Osteoarthritis Research Society International Terms and Conditions
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Fig. 2 The relationship of the tAB with height squared. (A) The least squares fit tAB=a×height2 applied to females and males together (a=0.0028, r2=0.67, P<0.0001). (B) The least squares fit b×sex+a×height2 where sex=0 or 1 for females or males, respectively (a=0.0028, b=9.54, r2=0.76, P<0.0001). (C) The least square fit for tAB=a×height2 with females only (a=0.0028, r2=0.60, P<0.0001). (D) The least squares fit for tAB=a×height2 with males only (a=0.0037, r2=0.16, P<0.01). () Females, (●) Males. Osteoarthritis and Cartilage , 34-40DOI: ( /j.joca ) Copyright © 2007 Osteoarthritis Research Society International Terms and Conditions
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Fig. 3 The relation of the VC for the total knee (K) with height cubed. (A) The least squares fit VC=a×height3 applied to females and males together (a=4.17×10−6, r2=0.54, P<0.0001). (B) The least squares fit VC=b×sex+a×height3 where sex=0 or 1 for females or males, respectively (a=3.69×10−6, b=4.38, r2=0.65, P<0.0001). (C) The least square fit for VC=a×height3 with females only (a=3.70×10−6, r2=0.38, P<0.0001). (D) The least squares fit for VC=a×height3 with males only (a=4.40×10−6, r2=0.09, P=0.03). () Females, (●) Males. Osteoarthritis and Cartilage , 34-40DOI: ( /j.joca ) Copyright © 2007 Osteoarthritis Research Society International Terms and Conditions
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