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Bellwork Friday 9.84 grams of aluminum is exposed to oxygen. How many moles of product are produced in this reaction?

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Presentation on theme: "Bellwork Friday 9.84 grams of aluminum is exposed to oxygen. How many moles of product are produced in this reaction?"— Presentation transcript:

1 Bellwork Friday 9.84 grams of aluminum is exposed to oxygen. How many moles of product are produced in this reaction?

2 Unit 8 ch 12 Part 2 Combination Problems

3 The mass from the periodic table!
A quick reminder… Let’s quickly remind ourselves of just how awesome a mole is! 1 mole = ________________particles 1 mole = ________________ liters 1 moles = _______________ grams 6.02 x 1023 22.4 The mass from the periodic table!

4 Combination Calculations:
At STP, how many grams of oxygen are needed to produce 19.8 liters SO3 according to the balanced equation below? 2SO2 (g) O2 (g)  2SO3 (g) 19.8 L SO3 1 mol SO3 1 mol O2 32.0 g O2 22.4 L SO3 2 mol SO3 1 mol O2 STP mol-mol ratio GFM 14.1 g O2 =


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