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Exercise How many different lunches can be made by choosing one of four sandwiches, one of three fruits, and one of two desserts? 24
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Exercise How many different lunches can be made by choosing one of four sandwiches, one of three fruits, one of two desserts, and one of two beverages? 48
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Exercise How many ways can four separate roles be filled if four people try out? 24
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Exercise How many ways can four separate roles be filled if seven people try out? 840
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Exercise How many ways can seven separate roles be filled if seven people try out? 5,040
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Permutation A permutation is a way of arranging r out of n objects (if r ≤ n).
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Fundamental Principle of Counting
If there are p ways that a first choice can be made and q ways that a second choice can be made, then there are p × q ways to make the first choice followed by the second choice.
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n Factorial The product of n natural numbers from n down to one is called n factorial. The symbol for “factorial” is an exclamation mark, and n! = n(n – 1) … (1). (0! = 1 by definition.)
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Example 1 Evaluate 6! 6(5)(4)(3)(2)(1) = 720
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Example Evaluate 5! 120
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Example Evaluate 8! 40,320
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Formula for the Permutation of n Objects Taken n at a Time—nPn
To find the number of permutations of n distinct objects taken n at a time, find the product of the positive integers n down through one: nPn = n(n – 1)(n – 2) … (2)(1) = n!
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Example 2 Find the number of permutations of the letters in the word saved.
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Formula for the Permutation of n Objects Taken r at a Time—nPr
To find the number of permutations of n distinct objects taken r at a time, use the formula nPr = n! (n – r)!
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Example 3 Find the number of permutations of the five letters s, a, v, e, and d taken three at a time. 5! (5 – 3)! = 5 x 4 x 3 x 2 x 1 2 x 1 = 5P3 = 5 x 4 x 3 = 60
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8(7)(6)(5)(4)(3)(2)(1) (5)(4)(3)(2)(1)
Example 4 Find the number of permutations of eight distinct things taken three at a time. 8! (8 – 3)! = 8! 5! = 8P3 8(7)(6)(5)(4)(3)(2)(1) (5)(4)(3)(2)(1) = = (8)(7)(6) = 336
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Example Evaluate 5P3. 60
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Example Evaluate 9P4. 3,024
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Example Find the number of ways ten books can be arranged on a bookshelf. 10P10 = 10! = 3,628,800
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Example Find the number of possible class schedules for a student taking six different classes. 6P6 = 6! = 720
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Example Find the number of different ways of choosing 17 committee chairpersons from the 51 senators in the majority party. 51P17 = 51! ÷ 34! = 5.25 × 1027
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Example In a race involving six people, how many different orders are possible for the top three finishers? 6P3 = 6! ÷ 3! = 120
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Example How many ways are there to select a jury foreman and subforeman from among the twelve jurors? 12P2 = 12! ÷ 10! = 132
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Example Find the number of ways of arranging ten books on a bookshelf if five are math books and five are history books and each category must be grouped together. 5! x 5! x 2 = 28,800
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Exercise Write an expression in the form nPr to represent the number of permutations in the following situations.
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Exercise Select first, second, and third place out of 500 contestants.
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Exercise Elect a president, vice president, secretary, and treasurer from a class of twenty-eight students. 28P4
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Exercise How many different two-digit whole numbers can you make from the digits 2, 4, 6, and 8 if no digit appears more than once in each number? 4P2
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Exercise How many different three-letter arrangements are there of the letters of the alphabet? 26P3
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