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Using Properties of Logarithms

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Presentation on theme: "Using Properties of Logarithms"โ€” Presentation transcript:

1 Using Properties of Logarithms

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3 Example Use the product rule to expand each logarithmic expression. ๐‘™๐‘œ๐‘” 3 9ยท5 ๐‘™๐‘œ๐‘” 1000๐‘ฅ

4 Solution Use the product rule to expand each logarithmic expression. ๐‘™๐‘œ๐‘” 3 9ยท5 = ๐‘™๐‘œ๐‘” 3 9 ยท ๐‘™๐‘œ๐‘” 3 5 ๐‘™๐‘œ๐‘” 1000๐‘ฅ =๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” ๐‘ฅ

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6 Example Use the quotient rule to expand each logarithmic expression. ๐‘™๐‘œ๐‘” ๐‘ฅ ๐‘™๐‘œ๐‘” ๐‘ฅ 8 ๐‘™๐‘› ๐‘’ 3 7

7 Solution Use the quotient rule to expand each logarithmic expression. ๐‘™๐‘œ๐‘” ๐‘ฅ = ๐‘™๐‘œ๐‘” โˆ’ ๐‘™๐‘œ๐‘” 5 ๐‘ฅ ๐‘™๐‘œ๐‘” ๐‘ฅ 8 =๐‘™๐‘œ๐‘” ๐‘ฅ โˆ’๐‘™๐‘œ๐‘” 8 ๐‘™๐‘› ๐‘’ =๐‘™๐‘› ๐‘’ 3 โˆ’๐‘™๐‘› 7

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9 Example Use the power rule to expand each logarithmic expression. ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” 2 8๐‘ฅ 4 ๐‘™๐‘œ๐‘” ๐‘ฅ ๐‘™๐‘› 6๐‘’ 5

10 Solution Use the power rule to expand each logarithmic expression. ๐‘™๐‘œ๐‘” =2 ๐‘™๐‘œ๐‘” 5 7 ๐‘™๐‘œ๐‘” 2 8๐‘ฅ 4 =4 ๐‘™๐‘œ๐‘” 2 8๐‘ฅ ๐‘™๐‘œ๐‘” ๐‘ฅ = 1 2 ๐‘™๐‘œ๐‘”๐‘ฅ ๐‘™๐‘› 6๐‘’ 5 =5๐‘™๐‘› 6๐‘’

11 Expanding Logarithmic Expressions

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13 Study Tip

14 Example Use logarithmic properties to expand each expression as much as possible. ๐‘™๐‘œ๐‘” ๐‘ ๐‘ฅ ๐‘ง ๐‘™๐‘œ๐‘” ๐‘ฆ 3 ๐‘™๐‘› 10 ๐‘’ ๐‘™๐‘œ๐‘”

15 Solutions Use logarithmic properties to expand each expression as much as possible. ๐‘™๐‘œ๐‘” ๐‘ ๐‘ฅ ๐‘ง 2 =2 ๐‘™๐‘œ๐‘” ๐‘ ๐‘ฅ ๐‘™๐‘œ๐‘” ๐‘ ๐‘ง =2 ๐‘™๐‘œ๐‘” ๐‘ ๐‘ฅ+ ๐‘™๐‘œ๐‘” ๐‘ ๐‘ง ๐‘™๐‘œ๐‘” ๐‘ฆ 3 =3 ๐‘™๐‘œ๐‘” 5 25โˆ’ ๐‘™๐‘œ๐‘” 5 ๐‘ฆ =3 2โˆ’ ๐‘™๐‘œ๐‘” 5 ๐‘ฆ =6โˆ’3 ๐‘™๐‘œ๐‘” 5 ๐‘ฆ ๐‘™๐‘› 10 ๐‘’ =๐‘™๐‘› 10 โˆ’๐‘™๐‘› ๐‘’ =๐‘™๐‘› 10 โˆ’1 ๐‘™๐‘œ๐‘” =๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” 10 =๐‘™๐‘œ๐‘”

16 Condensing Logarithmic Expressions

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18 Example Write as a single logarithm (condense) ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” 6๐‘ฅ โˆ’๐‘™๐‘œ๐‘” 6 2 ๐‘™๐‘œ๐‘” 3 9โˆ’ ๐‘™๐‘œ๐‘” 3 27 ๐‘™๐‘› ๐‘ฅโˆ’2 +5๐‘™๐‘› ๐‘ฅ

19 Solution Write as a single logarithm (condense)
๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” = ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” 6๐‘ฅ โˆ’๐‘™๐‘œ๐‘” 6=๐‘™๐‘œ๐‘” 6๐‘ฅ 6 =๐‘™๐‘œ๐‘” ๐‘ฅ 2 ๐‘™๐‘œ๐‘” 3 9โˆ’ ๐‘™๐‘œ๐‘” 3 27= ๐‘™๐‘œ๐‘” = ๐‘™๐‘œ๐‘” 3 3 =1 ๐‘™๐‘› ๐‘ฅโˆ’2 +5๐‘™๐‘› ๐‘ฅ=๐‘™๐‘› ๐‘ฅโˆ’2 ยท ๐‘ฅ 5 =๐‘™๐‘› ๐‘ฅ 5 ๐‘ฅโˆ’2

20 Question Can you simplify this any further?
๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” = ๐‘™๐‘œ๐‘”

21 Question Can you simplify this any further?
๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” = ๐‘™๐‘œ๐‘” How about this: ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” = ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” = ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” = = 7 2

22 The Change-of-Base Property

23 The Change-of-Base Property
Consider ๐‘™๐‘œ๐‘” 6 ๐‘ฅ. Can we find the value? One option would be to write this as a common logarithm and use our calculator: Let ๐‘™๐‘œ๐‘” 6 ๐‘ฅ=๐‘Ž. Then 6 ๐‘Ž =๐‘ฅ Take the log of both sides ๐‘™๐‘œ๐‘” 6 ๐‘Ž = ๐‘™๐‘œ๐‘” ๐‘ฅ What we want is a โ€“ thatโ€™s equal to the value of ๐‘™๐‘œ๐‘” 6 ๐‘ฅ ๐‘Žยท๐‘™๐‘œ๐‘” 6 = ๐‘™๐‘œ๐‘” ๐‘ฅ Solve for a ๐‘Ž = ๐‘™๐‘œ๐‘” ๐‘ฅ ๐‘™๐‘œ๐‘” So ๐‘™๐‘œ๐‘” 6 ๐‘ฅ= ๐‘™๐‘œ๐‘” ๐‘ฅ ๐‘™๐‘œ๐‘” 6

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25 Graphing Calculator

26 Example Use common logarithms to evaluate ๐‘™๐‘œ๐‘” 4 12 (Use change of base and your calculator)

27 Solution Use common logarithms to evaluate ๐‘™๐‘œ๐‘” 4 12 (Use change of base and your calculator) ๐‘™๐‘œ๐‘” 4 12= ๐‘™๐‘œ๐‘” 12 ๐‘™๐‘œ๐‘” 4 โ‰ˆ1.792

28 (a) (b) (c) (d)

29 ๐‘™๐‘œ๐‘” 9 81 ๐‘ฅ = ๐‘™๐‘œ๐‘” 9 81 โˆ’ ๐‘™๐‘œ๐‘” 9 ๐‘ฅ = ๐‘™๐‘œ๐‘” 9 9 2 โˆ’ ๐‘™๐‘œ๐‘” 9 ๐‘ฅ =2โˆ’ ๐‘™๐‘œ๐‘” 9 ๐‘ฅ
Answer is b (a) (b) (c) (d)

30 (a) (b) (c) (d)

31 (a) (b) (c) (d) ๐‘™๐‘œ๐‘” 3 27๐‘ฆ =๐‘™๐‘œ๐‘” 3 3 ๐‘ฆ =๐‘™๐‘œ๐‘” 3+๐‘™๐‘œ๐‘” 3 ๐‘ฆ Answer is b
๐‘™๐‘œ๐‘” 3 27๐‘ฆ =๐‘™๐‘œ๐‘” 3 3 ๐‘ฆ =๐‘™๐‘œ๐‘” 3+๐‘™๐‘œ๐‘” 3 ๐‘ฆ Answer is b Well, actually, answer is ๐‘™๐‘œ๐‘” ๐‘™๐‘œ๐‘” ๐‘ฆ (a) (b) (c) (d)


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