1. Solution stoich

2. c = n v concentration C. Solution Stoichiometry
use to perform calculations
concentration
c = n v

3. w g 2 KOH(aq) + 1 H2SO4(aq)  1 K2SO4(aq) + 2 H2O(l) v=? c= 14.8 mol/L
Example 1
What volume of 14.8 mol/L KOH is needed to react completely with 1.50 L of 12.9 mol/L sulphuric acid? w g 2
KOH(aq) + 1
H2SO4(aq)  1
K2SO4(aq) + 2
H2O(l)
v=?
c= 14.8 mol/L
v = 1.50 L
c = 12.9 mol/L
n = x 2 1
= mol
n = cv
= 12.9 mol/L x 1.50 L
= mol
v = n c
= mol
14.8 mol/L
= L
= 2.61 L