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Or Crossing two traits at a time
Di=Two! Dihybrid Crosses Or Crossing two traits at a time
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Crossing Two Traits at a Time
A man who is Heterozygous for Brown eyes(B) and Straight Hair(H) has children with a woman who is homozygous recessive for blue eyes(b) and curly hair(h). What percentage of their offspring would be heterozygous for both traits?
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STEP 1- Find your parents
A man who is Heterozygous for Brown eyes(B) and Straight Hair(H) has children with a woman who is homozygous recessive for blue eyes(b) and curly hair(h). ____________________________ X ____________________________
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Step 2- Set Up a Punnet Square for each trait
BbHh X bbhh
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Step 3- Multiply to find your answer
What percent of their offspring will be heterozygous for both traits? BbHh X bbhh B b Bb bb H h Hh hh Fraction of Heterozygous Brown Eyes Fraction of Heterozygous Straight Hair Fraction of Heterozygous for Both
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Fraction of Brown eyes and Curly Hair
How About Phenotypes? What percent of their offspring will have Brown eyes AND curly hair? BbHh X BbHh B b BB Bb bb H h HH Hh hh Fraction of Brown Eyes Fraction of Curly Hair Fraction of Brown eyes and Curly Hair
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Practice Problem 1 BBhh X BbHh
What percent of their offspring will be heterozygous for Brown eyes and homozygous recessive for curly hair? BBhh X BbHh
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Practice Problem 2 bbhh X BbHh
What percent of their offspring will have the genotype bbhh? bbhh X BbHh
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