1. Chapter 9 Lesson 4 Solve Linear Systems By Substitution

2. 6.2 Solving Systems by Substitution
Steps for Substitution
Substitute Value or expression into the other equation
Then…………..
Solve for remaining variable
(Equation should have only one variable)
Get variable VALUE……
Substitute the value into the starting equation to solve for OTHER variable
Write as ordered pair and check

3. Ex: Solve using substitution method
Now, solve for x
2x + 6x – 26 = -10
x = 2
Now substitute the 2 in for x in for the equation from step 1
Y = 3x - 13
y = -7
Solution: (2, -7)
y = 3x - 13
2x + 2y = -10
1st equation is solved for y
y = (3x - 13)
Now substitute (- 3x + 13) in for the y in the 2nd equation
2x + 2(3x - 13) = -10

4. Solve by Substitution
18x + 2y = 4
y = -3x + 8

5. Solve by Substitution!!
x = y + 3
2x + 2y = 2

6. Homework
Pg. 713 – 715
RC: 1 – 11, 15 – 21
HC: