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Oxidation Reduction Reactions
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Re-dox Reactions Oxidation is the loss of electrons
Reduction is a gain of electrons Leo goes Grr! Lose Electrons Oxidation Gain electrons Reduce
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“Redox Reactions” Many reactions involve (or seem to involve) a transfer of electrons. Such reactions always involve both: Oxidation Loss of electrons Na Na+ + e- Reduction Gain of electrons Cl + e- Cl-
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Determine a Redox Reaction
To determine if what you have is a redox reaction, first rewrite the equation to include the oxidation number for each element This includes every element in a polyatomic ion The oxidation number is the charge an element has or appears to have when combining to form compounds
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Oxidizing/Reducing Agents
The element that was oxidized is part of the reducing agent. The element that was reduced is part of the oxidizing agent.
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Assigning Oxidation Numbers
All pure elements and homogeneous molecules = 0 Elements in group IA = +1 Elements in group IIA = +2 Ag+, Zn+2, Al+3 (unless it is a pure metal) In binary compounds the second element = anion charge Oxygen is almost always = -2 *unless it is O2(g) Hydrogen is almost always = +1 *unless it is H2(g) The total charge of a compound is always = 0
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A Sample Problem What are the oxidation numbers of the elements in Na2SO4? Na = +1 (times 2 atoms) = +2 O = -2 (times 4 atoms) = -8 = -6 If the compound must = 0, then S must = +6
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Give the oxidation number for:
S in Na2SO3 Mn in KMnO4 N in Ca(NO3)2 C in Na2CO3 N in NO2- S in SO4-2 S in H2S2O7 Fe in Fe(C2H3O2)2 +4 +7 +5 +3 +6 +2
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Ammonia plus Oxygen NH3 + O2 NO + H2O Is this equation balanced?
No, it does not matter Step 1: Rewrite the equation with the charges N3-H+3 + O02 N2+O2- + H+2O2-
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Ammonia plus Oxygen Step 2: Determine the changes in the charges of each element N3-H+3 + O02 N2+O2- + H+2O2- Nitrogen changes from 3- to 2+ it lost an electron and was oxidized Oxygen changes from 0 to 2- it gains electrons and so is reduced
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Last Step Step 3: If there is a species oxidized and one reduced, then it is a redox equation
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