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Published byAriel Hopkins Modified over 5 years ago
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Warm-up: Why is the following not a piecewise-defined function?
Answer: There is an overlap of intervals, and f(4) is not unique. It can be 11 or 6.
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HW Key: p. 133: all B A D C
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Greatest Integer Functions
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Objectives & HW: The students will be able to graph and analyze Greatest Integer functions. HW: p. 134: even, 51, 55
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Step functions Your grades are based on a step function. Grade Scale
Letter grades have the following percentage equivalents: A B 80-89 C 70-79 D 60-69 E 0- 59
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Greatest Integer Function is a step function
The function is written as It is not an absolute value. The function rounds down to the last integer less than or equal to x.
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It may be helpful to visualize this function a little more clearly by using a number line.
1 2 3 4 5 6 7 8 -1 -2 -3 -4 -5 -6 -7 6.31 -6.31 Example: [6.31] = 6 Example: [-6.31] = -7 When you use this function, the answer is the integer on the immediate left on the number line. There is one exception. When the function acts on a number that is itself an integer. The answer is itself. Example: [5] = 5 Example: [-5] = -5 Example: Example:
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Find the value of a number in the Greatest Integer function f(x) =[x]
f(2.7) = 2 f(0.8) = 0 f(- 3.4) = - 4 It rounds down to the last integer less than or equal to x. Find the value f( 5.8) = f(⅛) = f(- ⅜) =
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f(x) = [x] x f(0) = [0] = 0 f(0.5) = [0.5] = 0 0.5 f(0.7) = [0.7] = 0 0.7 f(0.8) = [0.8] = 0 0.8 f(0.9) = [0.9] = 0 0.9 f(1) = [1] = 1 1 f(1.5) = [1.5] = 1 1.5 f(1.6) = [1.6] = 1 1.6 f(1.7) = [1.7] = 1 1.7 f(1.8) = [1.8] = 1 1.8 f(1.9) = [1.9] = 1 1.9 f(2) = [2] = 2 2 f(-0.5) =[-0.5]=-1 -0.5 f(-0.9) =[-0.9]=-1 -0.9 f(-1) = [-1] = -1 -1
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A step function graph
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How to graph a step function; f(x)= [x]
Find the values of x = .., -2, -1, 0, 1, 2, …… f(-2) = -2 f(-1) = - 1 f(0) = 0 f(1) = 1 f(2) = 2
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Now lets look at 0.5,1.5, -0.5, -1.5 f(-1.5) = -2 It is the same as f( - 2) = -2 f(-0.5) = f( - 1) = -1 f(0.5) = f(0) = 0 f(1.5) = f(1) = 1 So between 0 and almost 1 it equal 0 f( ) = 0
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How to show all those number equal 0
A close circle at (0, 0) and an open circle at (1, 0). (1, 0) What happens when x = 1?
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How to show all those number equal 0
A close circle at (0, 0) and an open circle at (1, 0). (1,1) (2,1) (1, 0) What happens when x = 1? It jumps to (1,1)
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Is the step only one unit long?
It will be in f(x) = [ x ]. Here is how I graph them. Find the fill in circles. Draw line segments ending in a open circle.
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How to graph a step function; f(x)= [x]
Find the values of x = .., -2, -1, 0, 1, 2, …… f(-2) = -2 f(-1) = - 1 f(0) = 0 f(1) = 1 f(2) = 2
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Graph: f(x) = 2[x]
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Graph: f(x) = -[x]
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Graph: f(x) = [-x]
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Graph: f(x) = [⅓ x]
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