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Piecewise-defined Functions
Dr. Fowler AFM Unit 1-4 Library of Functions; Piecewise-defined Functions
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The Square Root Function
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The Cube Root Function Copyright © 2013 Pearson Education, Inc. All rights reserved
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x and y intercepts are both 0.
This means the function is odd and symmetric with respect to the origin. x and y intercepts are both 0. Copyright © 2013 Pearson Education, Inc. All rights reserved
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The Absolute Value Function
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x and y intercepts are both 0.
This means the function is even and symmetric with respect to the y-axis. x and y intercepts are both 0. Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Copyright © 2013 Pearson Education, Inc. All rights reserved
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Piecewise Functions – “Function in Pieces” https://www. youtube
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Evaluating Piecewise Functions “a Function in Pieces”
Piecewise functions are functions defined by at least two equations, each of which applies to a different part of the domain A piecewise function looks like this: f(x) = x , x 0 x – 1 , x 0 Domain restrictions Equations
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f(x) = Evaluating Piecewise Functions:
Evaluating piecewise functions is just like evaluating functions that you are already familiar with. Let’s calculate f(2). f(x) = x , x 0 x – 1 , x 0 You are being asked to find y when x = 2. Domain Restrictions - Since 2 is 0, you will only substitute into the second part of the function. f(2) = 2 – 1 = 1
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f(x) = Let’s calculate f(-2). x2 + 1 , x 0 x – 1 , x 0
You are being asked to find y when x = -2. Since -2 is 0, you will only substitute into the first part of the function. f(-2) = (-2)2 + 1 = 5
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Try this example: Evaluate each piecewise function for x = –1 and x = 3. 3x if x < 0 g(x) = 5x – if x ≥ 0 Because –1 < 0, use the rule for x < 0. g(–1) = 3(–1)2 + 1 = 4 Because 3 ≥ 0, use the rule for x ≥ 0. g(3) = 5(3) – 2 = 13
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f(x) = Graphing Piecewise Functions: x2 + 1 , x 0 x – 1 , x 0
Determine the shapes of the graphs. Parabola and Line Determine the boundaries of each graph. Graph the line where x is greater than or equal to zero. Graph the parabola where x is less than zero.
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f(x) = Graphing Piecewise Functions: 3x + 2, x -2
Determine the shapes of the graphs. Line, Line, Parabola Determine the boundaries of each graph.
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Excellent Job !!! Well Done
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