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Linear Programming Mr. Carpenter Alg. 2
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Linear Programming Scenario
A manufacturer can make a profit of $6 on a bicycle and a profit of $4 on a tricycle. Department A requires 3 hours to manufacture a bicycle and 4 hours to manufacture a tricycle. Department B takes 5 hours to assemble a bicycle and 2 hours to assemble a tricycle. How many bicycles and tricycles should be produced to maximize the profit if the total time available in Department A is 450 hours and in Department B is 400 hours? Optimizing Equation: 6x + 4y = I Constraints: 3x + 4y ≤ 450 5x + 2y ≤ 400 Define the variables: X = # of bicycles produced Y = # of tricycles produced
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Graph Constraints Constraints: 3x + 4y ≤ 450 5x + 2y ≤ 400
Solved for y: y ≤ -3/4 x Y ≤ -5/2 x + 200
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Find the vertices (0, 11) (8, 0) (5, 7.5)
Vertices are the extremes of the “area of feasibility” (0, 11) (8, 0) (5, 7.5)
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Finding the maximum Optimizing Equation: 6x + 4y = I 3 vertices tested: (0, 11): 6(0) + 4(11) = 44 (8, 0): 6(8) + 4(0) = 48 (5, 7.5): 6(5) + 4(7.5) = 60 By producing 50 bicycles and 75 tricycles we make the maximum amount of income: $600.00
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