1. Q2 A baby drops a. 25 kg block out of a high rise window
Q2 A baby drops a .25 kg block out of a high rise window. What is the force on Earth due to the block, and what is Earth’s resulting acceleration? The mass of Earth is 6.0 x kg.
mblock = kg earth = 6.0 x kg
g = 9.8 m/s2 F earth on block = ? aearth = ?
F earth on block = mblock a = .25 kg (-9.8 m/s2)
F earth on block = kg*m/s2 = N

2. F earth on block = -2.54 N (from 1st problem solved)
Use Newton’s third Law to find F block on earth
mblock = kg m earth = 6.0 x kg
F earth on block = N (from 1st problem solved)
F block on earth = -F earth on block
F block on earth = -(-2.54N)
F block on earth = 2.54 N
F earth on ball =

3. Substitute: Fnet = m earth a earth 2.54 N = 6.0 x 10 24 kg * a earth
Use Newton’s Second law to find the aearth because of the net force caused by the block hitting it.
Fnet = 2.54 N m earth = 6.0 x kg
Substitute: Fnet = m earth a earth
2.54 N = 6.0 x kg * a earth
6.0 x kg x kg
4.2 X N/kg = a earth
3 X m/s 2 = a earth
kg * m/s2 kg