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Published byMark Smit Modified over 5 years ago
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Concept 7: The Second Fundamental Theorem of Calculus
Info Only The First Fundamental Theorem of Calculus was defined as: π π π(π₯) ππ₯ And represented a numerical value where π and π were fixed values
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Concept 7: The Second Fundamental Theorem of Calculus
The Second Fundamental Theorem of Calculus was defined as: π ππ₯ π π₯ π π‘ ππ‘ =π(π₯)
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Concept 7: The Second Fundamental Theorem of Calculus
π ππ₯ π π₯ π π‘ ππ‘ =π(π₯) πΉβ²(π₯)=π(π₯)
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Example 7A: Putting the MENTAL in Fundamental
Use the Second Fundamental Theorem of Calculus to find πΉβ²(π₯) πΉ π₯ = β1 π₯ π‘ 4 +1 ππ‘
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Example 7A: Putting the MENTAL in Fundamental
π ππ₯ π π₯ π π‘ ππ‘ =π(π₯)
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Example 7A: Putting the MENTAL in Fundamental
πΉ π₯ = β1 π₯ π‘ ππ‘ πΉβ² π₯ = π₯ 4 +1
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Itβs spelled βNunβ And youβre not funny Get it? None There is no SLE
Student Led Example 7A And youβre not funny Get it? None There is no SLE
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Example 7B: Using the Second Fundamental Theorem of Calculus
Info Only Or as it should be called: An introduction to βu substitutionβ And Chain Rule for Integrals
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Example 7B: Using the Second Fundamental Theorem of Calculus
Find πΉ β² π₯ Chain Rule πΉ β² π₯ = ππΉ ππ’ β
ππ’ ππ₯
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Example 7B: Using the Second Fundamental Theorem of Calculus
We need a π’ for this to work Because πΉ β² π₯ = ππΉ ππ’ β
ππ’ ππ₯ π ππ’ πΉ π₯ ππ’ ππ₯ Let π’= π₯ 2 Chain Rule Definition
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Example 7B: Using the Second Fundamental Theorem of Calculus
πΉ β² π₯ = ππΉ ππ’ β
ππ’ ππ₯ π ππ’ 0 π₯ 2 sin π 2 ππ ππ’ ππ₯ = π ππ’ 0 π’ sin π 2 ππ ππ’ ππ₯
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Example 7B: Using the Second Fundamental Theorem of Calculus
πΉ β² π₯ = ππΉ ππ’ β
ππ’ ππ₯ sin π 2 β sin π’ 2 π ππ’ 0 π’ sin π 2 ππ ππ’ ππ₯ sin π’ 2 β sin π₯ 2 2 ππ’ ππ₯ =2π₯
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Example 7B: Using the Second Fundamental Theorem of Calculus
πΉ β² π₯ = ππΉ ππ’ β
ππ’ ππ₯ β sin π₯ (2π₯) 2π₯ sin π₯ 4
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Example 7B: An Intro to u-substitution
Find the derivative of: πΉ π₯ = π 2 π₯ 3 cos π‘ ππ‘ Using the second fundamental theorem
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