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From description From Data From a graph

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Presentation on theme: "From description From Data From a graph"— Presentation transcript:

1 From description From Data From a graph
Calculating rxn rates From description From Data From a graph

2 Please write From description Ex 1
A bottle of wine contains ~72.0 g of ethyl alcohol, C2H5OH. When left open, the ethyl alcohol changes into acetic acid (vinegar) C2H5OH + O2  CH3COOH + H2O The wine changed completely into vinegar after 60 days. What is the average reaction rate(mol/d), of this transformation?

3 Please check 1. Calculate # of moles of alcohol.
1𝑚𝑜𝑙C2H5OH 𝑥 = 46.08𝑔 72.0𝑔 x = 1.56 mol of C2H5OH 2. Calculate the average rate: Rate = Rate = 1.56 / 60 Rate = mol/day 2.60x10-2mol/day

4 From description Ex 2 Below is a balanced equation: A + B  C + 2D A student dissolved 0.15 mol of substance A in solution B. After a 10 minutes, 0.05 mol of A is left. What is the average rate of formation of D in mol/sec?

5 1. Calculate moles of A used in 10 min: 0.15 – 0.05 mol = 0.10 mol A
Rxn: A + B  C + 2D 1. Calculate moles of A used in 10 min: 0.15 – 0.05 mol = 0.10 mol A 2. Calculate the moles of D produced: moles of D produced = 0.20 mol 3. Calculate the rxn time in sec: time = 10 x 60 =600 sec Rate = 4. Calculate the average rate: Rate = 0.20 / 600 Rate =3.3 x 10-4 mol/sec

6 Please write From data Ex 1
The combustion of a candle is recorded below. Before combustion After combustion Mass of candle (g) 165.5 162.0 Time (h:min) 1:00 6:00 Molar mass C25H52 = g/mol C25H O2  25 CO H2O Calculate the average rate of rxn in mol/h.

7 Please write 1. Calculate the # moles burned: 165.5 – 162.0 = 3.5 g
1𝑚𝑜𝑙C25H52 𝑥 = 𝑔 3.5𝑔 x = mol of candle burned 2. Calculate the average rate: Rate = Rate = / 5 Rate = mol/hr are burned 2.0 x 10-3 mol/hr

8 Please write From data A + B  C
1. # mol C after 3s = 0.25 mol 2. Average rate of C formation: Rate = Rate = 0.25 / 3 Rate = mol/s of C Find the average rate for the formation of C during the first three seconds?

9 Ex 2 Mg + 2HCl  H2 + MgCl2. The following table shows the volume of H2 formed during the reaction as a function of time. Time (s) Volume of H2 (mL) 10 50 100 150 8 32 45 What is the average rate of formation of H2 between the 25th and 75th second? Vol of H2 = 39mL – 19mL Rate = = 20 50 = 0.40mL/s = 20 mL

10 Average vs Instantaneous Rates
Please write Average vs Instantaneous Rates Average rate is found by picking two points in time and calculating the slope of the secant between them. Instantaneous rate is found by picking one point, and drawing a tangent. The slope of the tangent is then calculated. Δt tangent ΔA Amount secant ΔA Instantaneous Δt Average 2 4 7 Time

11 Rate equation for complex rxns:
Please write Rate equation for complex rxns: Rxns that proceed in multiple steps don’t always follow the predicted rate equation! Why? Because there are multiple activated complexes. The rate limiting step will have the greatest effect on the rate. The rate equation is determined experimentally A + 2B  C predicted rate=k[A][B]2 Let’s check according to experimental data!

12 Please write [A] [B] Rate (mol/Ls) 1 0.100 M 0.600 M 3.30 x 10-5 2
A + 2B  C rate=k[A]x[B]y Experiment [A] [B] Rate (mol/Ls) 1 0.100 M 0.600 M 3.30 x 10-5 2 0.300 M 1.65 x 10-5 3 5.50 x 10-6 4 0.200 M 2.20 x 10-5

13 Please write = = Compare exp 1 & 2
𝒓𝒂𝒕𝒆 𝟏=𝒌 𝑨 𝒙 𝑩 𝒚 𝒓𝒂𝒕𝒆 𝟐=𝒌 𝑨 𝒙 𝑩 𝒚 𝟑.𝟑𝟎× 𝟏𝟎 −𝟓 =𝒌 𝟎.𝟏𝟎𝟎 𝒙 𝟎.𝟔𝟎𝟎 𝒚 𝟏.𝟔𝟓× 𝟏𝟎 −𝟓 =𝒌 𝟎.𝟏𝟎𝟎 𝒙 𝟎.𝟑𝟎𝟎 𝒚 𝟐= 𝟎.𝟔𝟎𝟎 𝟎.𝟑𝟎𝟎 𝒚 𝟐= 𝟐 𝒚 𝒚=𝟏 =

14 Please write = = Compare exp 3 & 4 𝒓𝒂𝒕𝒆 𝟒=𝒌 𝑨 𝒙 𝑩 𝒚 𝒓𝒂𝒕𝒆 𝟑=𝒌 𝑨 𝒙 𝑩 𝒚
𝒓𝒂𝒕𝒆 𝟒=𝒌 𝑨 𝒙 𝑩 𝒚 𝒓𝒂𝒕𝒆 𝟑=𝒌 𝑨 𝒙 𝑩 𝒚 𝟐.𝟐𝟎× 𝟏𝟎 −𝟓 =𝒌 𝟎.𝟐𝟎𝟎 𝒙 𝟎.𝟏𝟎𝟎 𝒚 𝟓.𝟓𝟎× 𝟏𝟎 −𝟔 =𝒌 𝟎.𝟏𝟎𝟎 𝒙 𝟎.𝟏𝟎𝟎 𝒚 𝟒= 𝟎.𝟐𝟎𝟎 𝟎.𝟏𝟎𝟎 𝒙 𝟒= 𝟐 𝒙 𝒙=𝟐 =

15 Please write A + 2B  C rate=k[A]2[B]
Solve for k : rate=k[A]2[B] 3.30 x 10-5mol/Ls = k (0.100 mol/L)2(0.600 mol/L) 3.30 x 10-5mol/Ls = k (6.00 x 10-3 mol3/L3) k=5.50 x 10-3 𝑚𝑜𝑙 𝐿𝑠 𝑚𝑜𝑙 3 𝐿 3 k=5.50 x 10-3 𝑚𝑜𝑙 𝐿𝑠 × 𝐿 3 𝑚𝑜𝑙 3 k= 5.50 x 10-3 𝐿 2 𝑚𝑜𝑙 2 𝑠

16 Predicting Rates of Reactions:
Reactions that have reactants: 1. With oppositely charged ions are very fast 2. With few or weak bonds are faster than those with many or strong bonds Ag+ + Cl-  AgCl Faster Mg + HCl  MgCl + H2 C2H5OH + 3O2  2CO2 + 3H2O

17 Faster Faster 3. Gases > aqueous/liquids > solids
One step is faster than multiple (unless a catalyst is being used!) Faster H2 (g) + F2 (g)  2HF (g) Mg (s) + 2H2O (l)  2Mg2+ (aq) + 2OH- (aq) + H2 (g) 4NH3 (g) + 7O2 (g)  4NO2 (g) + 6H2O (g) Faster 2H2 (g) + O2 (g)  2H2O (g)

18 Predicting rxn rates: Primary effect on rxn rate (for a particular rxn!) Temperature Concentration Surface area Nature of material Catalyst

19 Please write Predicting rxn rates: Reactants that
Fastest of all due to static attraction! Reactants that are have oppositely charged ions Gases > aqueous/liquids > solids with few or weak bonds (ionic bonds are weaker than covalent) Bi-molecular collisions are faster than multi- molecular collisions

20 Fastest --> Slowest
Rank the following from fastest to slowest. 1. H2 (g) + F2 (g)  2HF(g) Ag+(aq) + Cl-(aq)  AgCl(aq) 2. 3. C2H5OH(aq) + 3O2(g)  2CO2(g) + 3H2O(l) Fastest --> Slowest 2 1 3

21 4NH3 (g) + 7O2 (g)  4NO2 (g) + 6H2O (g)
Which would have the greatest rate? A. Hg (l) + Br2 (g)  HgBr2 (s) B. 2H2 (g) + O2 (g)  2H2O (g) C. Ag+ (aq) + Cl- (aq)  AgCl (s) D. 4NH3 (g) + 7O2 (g)  4NO2 (g) + 6H2O (g) C

22 Hand in Homework & do Textbook practice
3 5 tricky (must use gas law also) P225 4


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