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Objective Students will find the slope of a line using 2 points.
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Vocabulary Rise Slope = Run Slope describes the steepness of a line.
Slope is the ratio of the rise (or vertical change) to the run (or the horizontal change) Vertical Change Rise Slope = Run Horizontal Change
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4.4 Slope 4 2 2 Rise Slope = Run Slope (m) = =
You get the x and y-values from any two points on the line. In this instance the ordered pairs are listed Rise Slope = x y (1, 2) (-1,-2) Run 4 Slope (m) = 2 = 2
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4.4 Slope 2 1 2 Rise Slope = Run Slope (m) = =
You get the x and y-values from any two points on the line. In this instance the ordered pairs are listed Rise Slope = x y (1, 1) (-1,-1) Run 2 Slope (m) = = 1 2
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4.4 Slope 3 βπ -1 Rise Slope = Run Slope (m) = =
You get the x and y-values from any two points on the line. In this instance the ordered pairs are listed Rise x y Slope = Run 3 Slope (m) = βπ = -1
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Finding Slope with a Formula
The formula for slope is: y2 β y1 x2 β x1 m =
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Example π βπ y2 β y1 x2 β x1 (βπ,π) (π,βπ) (βπ) β 3 3 β (βπ)
You get the x and y-values from any two points on the line. In this instance the ordered pairs are listed y2 β y1 x2 β x1 m = 1. Write the formula (βπ,π) (π,βπ) (βπ) β 3 3 β (βπ) m = (x1,y1) (x2,y2) 2. Substitute βπ π m = 3. Simplify
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1. Find the slope of a line passing through the points (βπ, βπ) πππ
(π, π) 2. Find the average rate of change of a line passing through the points (π, βπ) πππ
(π, βπ) (ππ , ππ) (ππ, ππ) (ππ, ππ) ( ππ, ππ) y2 β y1 x2 β x1 m = y2 β y1 x2 β x1 m = 6 β (- 2) 1 β (- 3) m = βπ β (βπ) 9 β 2 m = π π 8 4 m = 5 7 m = 2
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1. Find the slope of a line passing through the points (βπ, βπ) πππ
(π, π) 2. Find the average rate of change of a line passing through the points (π, π) πππ
(βπ, π) (ππ , ππ) (ππ, ππ) (ππ, ππ) ( ππ, ππ) y2 β y1 x2 β x1 m = y2 β y1 x2 β x1 m = 1 β (βπ) 3 β (βπ) m = π β π βπβπ m = π -14 m = π π 4 m =
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You decide to go on a diet. On the first day you weighed 100 lbs
You decide to go on a diet. On the first day you weighed 100 lbs., and on the fifth day you weighed 97 lbs. Find the average rate of change for your diet plan passing through the points (1, 100) and (5, 97) (ππ, ππ) ( ππ, ππ) y2 β y1 x2 β x1 m = 1. Write the formula 97 β 100 5 β 1 m = 2. Substitute βπ 4 m = 3. Simplify β π π πππππ
π π π
ππ
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Visual Representation of Slope
You can tell the slope of a line just by looking at itβ¦ The slope of a line can be either positive, negative, zero or undefinedβ¦
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Positive Slope x y
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Negative Slope x y
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Zero Slope x y
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Undefined Slope x y
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You are saving money for retirement
You are saving money for retirement. After the first year you have $3000, and after the tenth year you have $21,000. Find the average rate of change for your retirement savings. 1. π , ππππ (ππ, πππππ) 21000 β 3000 10 β 1 m = (ππ, ππ) ( ππ , ππ) $ππππ π ππππ 18000 9 m = 2. Find the slope of a line passing through the points ( 6, 1) and ( 6, 4) (ππ, ππ) ( ππ, ππ) πΌππ
ππππππ
3 m = 4 β 1 6 β 6 m =
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You are saving money for college
You are saving money for college. After the first year you have $3000, and after the thirteenth year you have $39,000. Find the average rate of change for your college savings. 1. π , ππππ (π, πππππ) 39000 β 3000 13 β 1 m = (ππ, ππ) ( ππ , ππ) $ππππ π ππππ 36000 12 m = 2. Find the slope of a line passing through the points ( 2, 1) and ( 4, βπ) (ππ, ππ) ( ππ, ππ) β π π βπ 2 m = β π β 1 4 β 2 m =
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4.4 Slope Find the value of y. ( 0, y) and ( 2, 5) m=2 (x1,y1) (x2,y2) y2 β y1 x2 β x1 m = 1. Write the formula 5 β y 2 β 0 2 = 2. Substitute π= π β π 5 - y 2 = βπ βπ (2) (2) βπ=β π π= π
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Find the value of y. ( 0, - 2) and ( 2, y) π=π 1. 2. Find the value of y. (- 3, - 3) and ( -2, y) π=π (x1,y1) (x2,y2) (x1,y1) (x2,y2) y2 β y1 x2 β x1 m = y2 β y1 x2 β x1 m = y β (-3) -2 β (-3) 5 = y β (-2) 2 β 0 3 = y + 3 1 5 = y + 2 2 3 = (2) (2) π= π+π π= π+π βπ βπ βπ βπ π= π π= π
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4.4 The Slope of a line 1. Slope describes the steepness of a line & is found with the ratio: Slope (m)= πΉπππ πΉππ = (ππππππ πππππππ ππππππ) (ππππππ πππππππ ππππππ) βββ’ π β’ π πΉπππ πΉππ = π ππ π πππππ β +π +π =π 2. There are four types of slopes: β’ Positive βRises up to the right Negative βDrops down to the right Zero βFlat or horizontal Undefinedβvertical (broken function)
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4.4 The Slope of a line Positive Negative Zero Undefined
(Weβve seen these before) πΌπ πΉππππ = πΌπ π³πππ = + β π²=# π=# (or) (or) π«πππ π³πππ = β β π«πππ πΉππππ = β πΉπππ π πΉππ # πΉπππ # πΉππ π Both are Both are Canβt Γ·π! π= π=β NO Slope x y x y x y x y
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4.4 The Slope of a line 1. Slope can be found without a graph if you know 2 points from the line. Slope (m)= πΉπππ πΉππ = πͺπππππ ππ π πͺπππππ ππ π = π π β π π π π β π π *Find m given (3,2) & (-4,1) (π π , π π ) (π π , π π ) π= πβπ βπβπ = βπ βπ = π π ππ π= πβπ πβ(βπ) = π π
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