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Published byOddbjørg Christophersen Modified over 5 years ago
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Replace inside with “x” of other function
(f g)(x) = f(g(x)) f(x)= x + 1 g(x) = 2x -1 f(g(x)) Inside first 2x–1 ( ) + 1 Replace inside with “x” of other function X 2x evaluate 2x
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Replace inside with “X” of other function
(f g)(x) = f(g(x)) f(x) = x g(x) = 2x + 1 2 f(g(x)) Inside First ( ) 2x + 1 2 Replace inside with “X” of other function X Evaluate (2x + 1)(2x + 1) 4x + 4x + 1 2
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g(x) = x + 1 f(x) = x - 2 (g f)(x) = g(f(x)) ( ) + 1 x - 2
( ) + 1 x - 2 2 (x-2)(x-2) + 1
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h(x) = x + 2x -1 g(x) = 4x -5 h g(x)) (4x – 5) (4x – 5) +2 -1
2 (4x – 5)(4x – 5) +8x – 10 -1 16x – 20x – 20x x 2 16x -32x +14 2
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f(x) = 2x -x -4 g(x) = -5x + 4 f g (x) 2 - -4 (-5x + 4) (-5x + 4)
(-5x + 4) (-5x + 4) 2 2(-5x + 4)(-5x + 4) +5x -4 -4 2(25x -20x -20x + 16) +5x -4 -4 2 50x -40x -40x x -4 -4 2 50x -75x +24 2
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f(x) = 2x -x +4 g(x) = 5x + 3 (g f)(x) g(f(x)) 5( ) +3 2x – x + 4
5( ) +3 2x – x + 4 3 10x -5x 3 10x -5x + 23 3
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