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Graphing Quadratic Functions

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Presentation on theme: "Graphing Quadratic Functions"— Presentation transcript:

1 Graphing Quadratic Functions
Lesson 5-1 Part 3

2 MAIN IDEAS How to determine if the function has a Minimum or a Maximum value State the maximum of minimum value of the function State the domain and range of the function

3 MINIMUM OR MAXIMUM For the graph of f(x) = ax2 + bx + c where a ≠ 0
When a > 0 the graph opens UP and has a MINIMUM When a < 0 the graph opens DOWN and has a MAXIMUM

4 Example of MAXIMUM or MINIMUM
Consider the function f(x) = x2 – 6x + 8 Determine a, b, c → a= 1, b= -6, c= 8 Since a > 0, the graph opens UP and has a MINIMUM For f(x) = - x2 + 2x + 3 Determine a, b, c → a= -1, b= 2, c= 3 Since a < 0 the graph opens DOWN and has a MAXIMUM

5 STATING THE VALUE OF THE MINIMUM OR MAXIMUM
The maximum/minimum value of the function is the y-coordinate of the vertex For example in the function f(x) = x2 – 6x + 8 we determine the vertex by finding the axis of symmetry, plugging that value back into the function to find the y-coordinate -b/2a = -(-6)/2(1) = 6/2 = 3 f(3) = (3)2 – 6(3) + 8 = -1; the y-coordinate of the vertex is -1 The value of the MINIMUM (since a>0) is -1

6 YOUR TURN TO THE FIND VALUE OF THE MINIMUM OR MAXIMUM
State the maximum or minimum value for the function f(x) = 2x2 + 5x + 3 Determine if the graph has a Minimum or Maximum a=2; a>0 so it opens UP and has a MINIMUM find the axis of symmetry, -b/2a -(5)/2(2) = -5/4 = -1.25 - Plug that value back into the function to find the y-coordinate f(-1.25) = 2(-1.25)2 +5(-1.25) + 3 = – = the y-coordinate of the vertex is The value of the MINIMUM is


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