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Warm Up Lesson Presentation Lesson Quiz.

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Presentation on theme: "Warm Up Lesson Presentation Lesson Quiz."— Presentation transcript:

1 Warm Up Lesson Presentation Lesson Quiz

2 Warm Up ±5 1. Write a similarity statement
comparing the two triangles. Simplify. Solve each equation. x2 = 50 ∆ADB ~ ∆EDC ±5

3 Objectives Use geometric mean to find segment lengths in right triangles. Apply similarity relationships in right triangles to solve problems.

4 Vocabulary geometric mean

5 In a right triangle, an altitude drawn from the vertex of the right angle to the hypotenuse forms two right triangles.

6

7 Example 1: Identifying Similar Right Triangles
Write a similarity statement comparing the three triangles. Sketch the three right triangles with the angles of the triangles in corresponding positions. Z W ∆UVW ~ ∆UWZ ~ ∆WVZ.

8 TEACH! Example 1 Write a similarity statement comparing the three triangles. Sketch the three right triangles with the angles of the triangles in corresponding positions. ∆LJK ~ ∆JMK ~ ∆LMJ.

9 Consider the proportion
Consider the proportion In this case, the means of the proportion are the same number, and that number is the geometric mean of the extremes. The geometric mean of two positive numbers is the positive square root of their product. So the geometric mean of a and b is the positive number x such that , or x2 = ab.

10 Example 2A: Finding Geometric Means
Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 4 and 25 Let x be the geometric mean. x2 = (4)(25) = 100 Def. of geometric mean x = 10 Find the positive square root.

11 TEACH! Example 2a Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 2 and 8 Let x be the geometric mean. x2 = (2)(8) = 16 Def. of geometric mean x = 4 Find the positive square root.

12 You can use Theorem to write proportions comparing the side lengths of the triangles formed by the altitude to the hypotenuse of a right triangle. All the relationships in red involve geometric means.

13

14 Example 3: Finding Side Lengths in Right Triangles
Find x, y, and z. 62 = (9)(x) 6 is the geometric mean of 9 and x. x = 4 Divide both sides by 9. y2 = (4)(13) = 52 y is the geometric mean of 4 and 13. Find the positive square root. z2 = (9)(13) = 117 z is the geometric mean of 9 and 13. Find the positive square root.

15 Once you’ve found the unknown side lengths, you can use the Pythagorean Theorem to check your answers. Helpful Hint

16 92 = (3)(u) 9 is the geometric mean of
TEACH! Example 3 Find u, v, and w. 92 = (3)(u) is the geometric mean of u and 3. u = Divide both sides by 3. w2 = (27 + 3)(27) w is the geometric mean of u + 3 and 27. Find the positive square root. v2 = (27 + 3)(3) v is the geometric mean of u + 3 and 3. Find the positive square root.

17 Example 4: Measurement Application
To estimate the height of a Douglas fir, Jan positions herself so that her lines of sight to the top and bottom of the tree form a 90º angle. Her eyes are about 1.6 m above the ground, and she is standing 7.8 m from the tree. What is the height of the tree to the nearest meter?

18 Let x be the height of the tree above eye level.
Example 4 Continued Let x be the height of the tree above eye level. 7.8 is the geometric mean of 1.6 and x. (7.8)2 = 1.6x x = ≈ 38 Solve for x and round. The tree is about = 39.6, or 40 m tall.

19 TEACH! Example 4 A surveyor positions himself so that his line of sight to the top of a cliff and his line of sight to the bottom form a right angle as shown. What is the height of the cliff to the nearest foot?

20 TEACH! Example 4 Continued
Let x be the height of cliff above eye level. (28)2 = 5.5x 28 is the geometric mean of 5.5 and x. x  142.5 Divide both sides by 5.5. The cliff is about , or 148 ft high.

21 Lesson Quiz: Part I Find the geometric mean of each pair of numbers. If necessary, give the answer in simplest radical form. 1. 8 and 18 2. 6 and 15 12

22 Lesson Quiz: Part II For Items 3–6, use ∆RST. 3. Write a similarity statement comparing the three triangles. 4. If PS = 6 and PT = 9, find PR. 5. If TP = 24 and PR = 6, find RS. 6. Complete the equation (ST)2 = (TP + PR)(?). ∆RST ~ ∆RPS ~ ∆SPT 4 TP


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