1. Equations – Success if you can do these
3x = 6
4x + 2 = 3x + 7
x/4 = 2
5x – 3 = 7 + 3x
x + 3 = 17
3(x + 2) = 12
x – 4 = 13
4(x + 5) = 32
3x + 4 = 25
3(2x – 2) = 2(x + 6)
4x – 3 = 17
4(3x + 5) = 2(x + 15)

2. How to solve the 5x = 20 type of equation
5 and 20
can be any number

3. 5x = 20 means
5 X x = 20
5x = 20
5 X x = 20

4. So, you get rid of the 5 X by ÷ 5
5x = 20 means
5 X x = 20
So, you get rid of the 5 X by ÷ 5
5x = 20
5 X x ÷ 5 = 20 ÷ 5

5. So, you get rid of the 5 X by ÷ 5
5x = 20 means
5 X x = 20
So, you get rid of the 5 X by ÷ 5
5x = 20
5 X x ÷ 5 = 20 ÷ 5
x = 4

6. 5x = 20 means
5 X x = 20
So, you get rid of the 5 X by ÷ 5
5x = 20
5 X x ÷ 5 = 20 ÷ 5
x = 4
But you must divide both sides by 5

7. just divide both sides by the number that multiplies the x.
For equations like
5x = 20
just divide both sides by the number that multiplies the x.
5x = 20
x = 20 ÷ 5
x = 4
Like this

8. How to solve the x/3 = 4 type of equation
The 3 and 4
can be any number

9. It means x ÷ 3 = 4
x/3 = 4
x ÷ 3 = 4

10. x/3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 X 3 It means x ÷ 3 = 4 Get rid of
÷ 3 by using a
X 3

11. x/3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 x = 12 X 3 It means x ÷ 3 = 4
Get rid of
÷ 3 by using a
X 3

12. x/3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 x = 12 X 3 It means x ÷ 3 = 4
Get rid of
÷ 3 by using a
X 3
You must X 3 on both sides

13. just multiply both sides by the number that divides the x.
For equations like
x/3 = 4
just multiply both sides by the number that divides the x.
x/3 = 4
x = 4 X 3
x =12
Like this

14. Try these 1 2x = 16 7 x/4 = 2 2 3x = 21 8 x/2 = 3 3 5x = 35 9 x/4 = 510
x/5 = 6 5
2x = 7 11
x/8 = 7 6
5x = 12 12
x/9 = 10

15.                              
Remember, always do the same thing to both sides.
Felix is checking that you do this properly.
x/3 = 12
x ÷ 3 X 3 = 12 X 3
x =36