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Notes 6 ECE 3318 Applied Electricity and Magnetism Coordinate Systems
Spring 2019 Prof. David R. Jackson Dept. of ECE Notes 6 Coordinate Systems Notes prepared by the EM Group University of Houston
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Review of Coordinate Systems
An understanding of coordinate systems is important for doing EM calculations.
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Kinds of Integrals That Often Occur
We wish to be able to perform all of these calculations in various coordinates.
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Rectangular Coordinates
Position vector: Short hand notation: Note: We have the “tip to tail” rule when adding vectors. Note: A unit vector direction is defined by increasing one coordinate variable while keeping the other two fixed. Note: Different notations are used for vectors in the books.
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Rectangular Coordinates
Differentials We increase x, y, or z starting from an initial point (blue dot). Note: dS may be in three different forms.
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Rectangular (cont.) Path Integral (we need dr)
Note on notation: The symbol dl is often used instead of dr .
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Cylindrical Coordinates
.
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. Cylindrical (cont.) Unit Vectors Note: and depend on (x, y)
A unit vector direction is defined by increasing one coordinate variable while keeping the other two fixed. Note: and depend on (x, y) This is why we often prefer to express them in terms of
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Cylindrical (cont.) Expressions for unit vectors (illustrated for )
Assume Similarly, Solve for A1: so Hence, we have
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Cylindrical (cont.) Summary of Results
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cylindrical coordinates.
Cylindrical (cont.) . Example: Express the r vector in cylindrical coordinates. Substituting from the previous tables of unit vector transformations and coordinate transformations, we have
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Cylindrical (cont.) . Note:
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Cylindrical (cont.) Differentials
Note: dS may be in three different forms. We increase , , or z starting from an initial point (blue dot). Note: The angle must be in radians here.
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Note: The angle must be in radians here.
Cylindrical (cont.) Path Integrals First, consider differential changes along any of the three coordinate directions. Note: The angle must be in radians here.
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Note: A change in z is not shown, but is possible.
Cylindrical (cont.) Note: A change in z is not shown, but is possible. In general: If we ever need to find the length along a contour:
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Spherical Coordinates
. . Note: 0 Note: = r sin
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Spherical (cont.) . Note: = r sin
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Spherical (cont.) Unit Vectors Note:
A unit vector direction is defined by increasing one coordinate variable while keeping the other two fixed.
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Spherical (cont.) Transformation of Unit Vectors
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spherical coordinates.
Spherical (cont.) Example: Express the r vector in spherical coordinates. Substituting from the previous tables of unit vector transformations and coordinate transformations, we have:
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Spherical (cont.) After simplifying:
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Spherical (cont.) Differentials
We increase r, , or starting from an initial point (blue dot). Note: dS may be in three different forms (only one is shown). The other two are: Note: The angles and must be in radians here.
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Note: The angles and must be in radians here.
Spherical (cont.) Path Integrals Note: The angles and must be in radians here.
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Note on dr Vector Note that the formula for the dr vector never changes, no matter which direction we go along a path (we never add a minus sign!). Example: Integrating along a horizontal radial path in cylindrical coordinates. The limits take care of the sign of dr. Note: This form does not change, regardless of which limit is larger.
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Example Given: Find the current I crossing a hemisphere (z > 0) of radius a, in the outward direction. Hemisphere
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Example (cont.)
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Example (cont.)
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Appendix Here we work out some more examples.
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This formula only works in rectangular coordinates!
Example Cylindrical coordinates (, , z) Given: with distances in meters Find d = distance between points This formula only works in rectangular coordinates! d = [m]
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Example Find Q Solution: “A sphere with a hole in it” Note:
The integrand is separable and the limits are fixed. Find Q Solution: “A sphere with a hole in it”
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Example (cont.) Note: The average value of cos2 is 1/2.
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Example Derive Let Dot multiply both sides with Then
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Example (cont.) Result:
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(We use a two-step process.)
Example Derive Let Dot multiply both sides with An illustration of finding the x component of (We use a two-step process.)
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Example (cont.) Hence Similarly, Also, Result:
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Find VAB using path C shown below.
Example (Part 1) (This is not an electrostatic field.) Find VAB using path C shown below. .
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Example (cont.) Completing the calculus:
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Example (cont.) Alternative calculation (we parameterize differently):
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Find VAB using path C shown below.
Example (Part 2) (same field as in Part 1) Find VAB using path C shown below.
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Find VAB using an arbitrary path C in the xy plane.
Example (This is a valid electrostatic field.) Find VAB using an arbitrary path C in the xy plane. Note: The path does not have to be parameterized. Hence, only the endpoints are important. The integral is path independent!
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Example Note: If we have an electric field of the form:
(discussed later) VAB is path independent.
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Find VAB using path C shown below.
Example Find VAB using path C shown below.
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Example (cont.) Note: The angle must change continuously along the path. If we take the angle to be / 2 at point B, then the angle must be - at point A.
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Example (cont.) Let’s examine this same electric field once again:
Question: Is this integral path independent? Note: The answer is yes because the curl of the electric field is zero, but we will talk about curl later.
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Yes, it is path independent!
Example (cont.) Question: Is this integral path independent? Let’s find out from the calculus: Yes, it is path independent! Note: Even though the path was given as a circle, the calculus was easier in rectangular coordinates in this example!
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