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Calculating Ion Concentration from pH
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Calculating [Ion] from pH
We use logarithms to do this N = 10x, then log N = x [H+] = 10-pH [H+] = invlog(-pH) [OH-] = invlog(-pOH) On the calculator press 2nd log-pH#
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Calculations of [H+] or [OH-]
Ex 1: What are [H+] and [OH-] in a healthy person’s blood that has a pH = 7.40 at temp 298 K? Kw = [H+] x [OH-] 1 x = [3.98 x 10-8] x [OH-] 3.98 x x 10-8 2.51 x = [OH-] [H+] = invlog(-pH) [H+] = invlog(-7.40) [H+] = 3.98 x 10-8
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Calculations of [H+] or [OH-]
Ex 2: What are [H+] and [OH-] at a pH = 2.3? Kw = [H+] x [OH-] 1 x = [0.0050] x [OH-] 2.0 x = [OH-] [H+] = invlog(-pH) [H+] = invlog(-2.3) [H+] =
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Calculations of [H+] or [OH-]
Ex 3: What are [H+] and [OH-] at a pH = 5.54? Kw = [H+] x [OH-] 1 x = [2.88 x 10-6] x [OH-] 2.88 x x 10-6 3.47 x = [OH-] [H+] = invlog(-pH) [H+] = invlog(-5.54) [H+] = 2.88 x 10-6
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