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CSCE 715: Network Systems Security

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1 CSCE 715: Network Systems Security
Chin-Tser Huang University of South Carolina

2 Key Management Asymmetric encryption helps address key distribution problems Two aspects distribution of public keys use of public-key encryption to distribute secret keys 09/15/2011

3 Distribution of Public Keys
Four alternatives of public key distribution Public announcement Publicly available directory Public-key authority Public-key certificates 09/15/2011

4 Public Announcement Users distribute public keys to recipients or broadcast to community at large E.g. append PGP keys to messages or post to news groups or list Major weakness is forgery anyone can create a key claiming to be someone else’s and broadcast it can masquerade as claimed user before forgery is discovered 09/15/2011

5 Publicly Available Directory
Achieve greater security by registering keys with a public directory Directory must be trusted with properties: contains {name, public-key} entries participants register securely with directory participants can replace key at any time directory is periodically published directory can be accessed electronically Still vulnerable to tampering or forgery 09/15/2011

6 Public-Key Authority Improve security by tightening control over distribution of keys from directory Has properties of directory Require users to know public key for the directory Users can interact with directory to obtain any desired public key securely require real-time access to directory when keys are needed 09/15/2011

7 Public-Key Authority 09/15/2011

8 Public-Key Certificates
Certificates allow key exchange without real-time access to public-key authority A certificate binds identity to public key usually with other info such as period of validity, authorized rights, etc With all contents signed by a trusted Public-Key or Certificate Authority (CA) Can be verified by anyone who knows the CA’s public key 09/15/2011

9 Public-Key Certificates
09/15/2011

10 Distribute Secret Keys Using Asymmetric Encryption
Can use previous methods to obtain public key of other party Although public key can be used for confidentiality or authentication, asymmetric encryption algorithms are too slow So usually want to use symmetric encryption to protect message contents Can use asymmetric encryption to set up a session key 09/15/2011

11 Simple Secret Key Distribution
Proposed by Merkle in 1979 A generates a new temporary public key pair A sends B the public key and A’s identity B generates a session key Ks and sends encrypted Ks (using A’s public key) to A A decrypts message to recover Ks and both use 09/15/2011

12 Problem with Simple Secret Key Distribution
An adversary can intercept and impersonate both parties of protocol A generates a new temporary public key pair {KUa, KRa} and sends KUa || IDa to B Adversary E intercepts this message and sends KUe || IDa to B B generates a session key Ks and sends encrypted Ks (using E’s public key) E intercepts message, recovers Ks and sends encrypted Ks (using A’s public key) to A A decrypts message to recover Ks and both A and B unaware of existence of E 09/15/2011

13 Distribute Secret Keys Using Asymmetric Encryption
if A and B have securely exchanged public-keys ? 09/15/2011

14 Problem with Previous Scenario
Message (4) is not protected by N2 An adversary can intercept message (4) and replay an old message or insert a fabricated message 09/15/2011

15 Order of Encryption Matters
What can be wrong with the following protocol? AB: N BA: EKUa[EKRb[Ks||N]] An adversary sitting between A and B can get a copy of secret key Ks without being caught by A and B! Reverse the order of encryption using KRb and encryption using KUa can avoid this attack 09/15/2011

16 Diffie-Hellman Key Exchange
First publicly proposed public-key type scheme By Diffie and Hellman in 1976 along with advent of public key concepts A practical method for public exchange of secret key Used in a number of commercial products 09/15/2011

17 Diffie-Hellman Key Exchange
Use to set up a secret key that can be used for symmetric encryption cannot be used to exchange an arbitrary message Value of key depends on the participants (and their private and public key information) Based on exponentiation in a finite (Galois) field (modulo a prime or a polynomial) – easy Security relies on the difficulty of computing discrete logarithms (similar to factoring) – hard 09/15/2011

18 Primitive Roots From Euler’s theorem: aø(n) mod n=1
Consider am mod n=1, GCD(a,n)=1 must exist for m= ø(n) but may be smaller once powers reach m, cycle will repeat If smallest is m= ø(n) then a is called a primitive root if p is prime and a is a primitive root of p, then successive powers of a “generate” the group mod p Not every integer has primitive roots 09/15/2011

19 Primitive Root Example: Power of Integers Modulo 19
09/15/2011

20 Discrete Logarithms Inverse problem to exponentiation is to find the discrete logarithm of a number modulo p Namely find x where ax = b mod p Written as x=loga b mod p or x=dloga,p(b) If a is a primitive root of p then discrete logarithm always exists, otherwise may not 3x = 4 mod 13 has no answer 2x = 3 mod 13 has an answer 4 While exponentiation is relatively easy, finding discrete logarithms is generally a hard problem 09/15/2011

21 Diffie-Hellman Setup All users agree on global parameters
large prime integer or polynomial q α which is a primitive root mod q Each user (e.g. A) generates its key choose a private key (number): xA < q compute its public key: yA = αxA mod q Each user publishes its public key 09/15/2011

22 Diffie-Hellman Key Exchange
Shared session key for users A and B is KAB: KAB = αxA.xB mod q = yAxB mod q (which B can compute) = yBxA mod q (which A can compute) KAB is used as session key in symmetric encryption scheme between A and B Attacker needs xA or xB, which requires solving discrete log 09/15/2011

23 Diffie-Hellman Example
Given Alice and Bob who wish to swap keys Agree on prime q=353 and α=3 Select random secret keys: A chooses xA=97, B chooses xB=233 Compute public keys: yA=397 mod 353 = 40 (Alice) yB=3233 mod 353 = 248 (Bob) Compute shared session key as: KAB= yBxA mod 353 = = 160 (Alice) KAB= yAxB mod 353 = = 160 (Bob) 09/15/2011

24 Elliptic Curve Cryptography
Majority of public-key crypto (RSA, D-H) use either integer or polynomial arithmetic with very large numbers/polynomials Imposes a significant load in storing and processing keys and messages An alternative is to use elliptic curves Offers same security with smaller bit sizes 09/15/2011

25 Real Elliptic Curves An elliptic curve is defined by an equation in two variables x and y, with coefficients Consider a cubic elliptic curve of form y 2 = x 3 + ax + b where x, y, a, b are all real numbers also define zero point O Have addition operation for elliptic curve geometrically, sum of P+Q is reflection of intersection R 09/15/2011

26 Real Elliptic Curve Example
09/15/2011

27 Finite Elliptic Curves
Elliptic curve cryptography uses curves whose variables and coefficients are finite Two families are commonly used prime curves Ep(a,b) defined over Zp use integers modulo a prime best in software binary curves E2m(a,b) defined over GF(2m) use polynomials with binary coefficients best in hardware 09/15/2011

28 Elliptic Curve Cryptography
ECC addition is analog of modulo multiply ECC repeated addition is analog of modulo exponentiation Need a “hard” problem equivalent to discrete logarithm Q=kP, where Q, P belong to a prime curve is “easy” to compute Q given k, P but “hard” to find k given Q, P known as the elliptic curve logarithm problem Certicom example: E23(9,17) 09/15/2011

29 ECC Diffie-Hellman Can do key exchange analogous to D-H
Users select a suitable curve Ep(a,b) Select base point G=(x1, y1) with large order n s.t. nG=O A and B select private keys nA<n, nB<n Compute public keys: PA=nA×G, PB=nB×G Compute shared key: K=nA×PB, K=nB×PA same since K=nA×nB×G 09/15/2011

30 ECC Encryption/Decryption
Must first encode any message M as a point on the elliptic curve Pm Select suitable curve and point G as in D-H Each user chooses private key nA<n and computes public key PA=nA×G To encrypt Pm: Cm={kG, Pm+kPB}, k random To decrypt Cm: Pm+kPB–nB(kG) = Pm+k(nBG)–nB(kG) = Pm 09/15/2011

31 ECC Security Relies on elliptic curve logarithm problem
Fastest method is “Pollard rho method” Compared to factoring, ECC can use much smaller key sizes than with RSA For equivalent key lengths computations are roughly equivalent Hence for similar security ECC offers significant computational advantages 09/15/2011

32 Comparable Key Sizes 1 09/15/2011

33 Next Class Message authentication Hashing functions Message digests
Read Chapters 11 and 12 09/15/2011


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