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MAS2317 Presentation Question 1
Ryan Sheridan
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Question Suppose that 1% of the population have a disease D. A diagnostic test S, designed to detect the disease, has the following accuracy: Pr(S positive|D) = 0.95 and Pr (S positive|Dc) = If 100 people were tested at random, how many would we expect to test positive and of those that do, about how many would we expect to have the disease?
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How many would we expect to be positive?
Using the Law of Total Probability, Pr 𝐹 = 𝑖=1 𝑛 Pr 𝐹 𝐸 𝑖 Pr( 𝐸 𝑖 ) , we get; Pr +𝑣𝑒 = Pr +𝑣𝑒 𝐷 Pr 𝐷 + Pr +𝑣𝑒 𝐷 𝑐 Pr( 𝐷 𝑐 ) =0.95× ×0.99 =0.059 So out of 100 random people being tested we would expect about 6 people test positive regardless of if they have the disease or not.
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Now to find how many of those 6 people we expect to actually have the disease.
Using Bayes’ theorem we get, Pr 𝐷 +𝑣𝑒 = Pr +𝑣𝑒 𝐷 Pr(𝐷) Pr +𝑣𝑒 𝐷 Pr 𝐷 +𝑃𝑟 +𝑣𝑒 𝐷 𝑐 Pr( 𝐷 𝑐 ) = 0.95× × ×0.99 =0.161 So we now have the probability of getting a positive test and the probability of having the disease given a positive test, now to find the number of people to actually have the disease: 0.059×0.161×100%=0.9499% So we would expect only one person to actually have the disease given the test was positive for them.
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